Gaseous States Test

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Gaseous States Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

If the average velocity of N₂ molecules is 0.3 m/sec at 27^∘C, then the velocity of 0.6 m/sec will take place at :

A
273 K

B
927 K

C
1000 K

D
1200 K

Solution

The average velocity is directly proportional to the square root of the temperature.
Question 2
1 / -0

Containers A and B have same gas. Pressure, volume and temperature of A are all twice that of B. Then the ratio of the number of molecules of A and B are

A
1 : 2

B
2 : 1

C
1 : 4

D
4:1

Solution
Question 3
1 / -0

What is the pressure of 2 mole of NH₃ at 27^∘C when its volume is 5 lit. in can der Waal's equation ? (a=4.17,b=0.03711)

A
10.33 atm

B
9.333 atm

C
9.74 atm

D
9.2 atm

Solution
Question 4
1 / -0

The RMS velocity of an ideal gas at 27⁰C is 0.3 m/sec. Its RMS velocity at 927^oC is :

A
6 m/sec

B
0.3 m/sec

C
0.6 m/sec

D
3 m/sec

Solution
Question 5
1 / -0

The kinetic energy of 4 moles of nitrogen gas at 127 is: (R=2 cal mol⁻¹K⁻¹)

A
4400 cal

B
3200 cal

C
4800 cal

D
1524 cal

Solution
Question 6
1 / -0

At very high pressure, the compressibility factor of gas

A
Increases with increase of temperature

B
Decreases with increase of temperature

C
Remains constant with change in temperature

D
Is less than one

Solution

At very high pressure, volume V is very small. a/V2 is large but in comparison to high P it can be neglected. therefore van der Waals equation becomes

Z = PV/nRT.

Thus, compressibility factor is greater than one and decreases with increase of temperature
Question 7
1 / -0

When one mole of monoatomic ideal gas at T K undergoes adiabatic change under a constant external pressure of 1 atm changes volume from 1 litre to 2 litres. The final temperature in Kelvin would be?

A

B

C
T

D

Solution
Question 8
1 / -0

The average kinetic energy of an ideal gas per molecule in SI units at 25^∘C will be :

A
6.17×10⁻²¹ kJ

B
6.17×10⁻²¹ J

C
6.17×10⁻²⁰ J

D
7.16×10⁻²⁰ J

Solution
Question 9
1 / -0

If r.m.s. speed of gaseous molecules is x cm/sec at a pressure of p atm r.m.s. at a pressure of 2p atm and constant temperature will be

A
x

B
2x

C
4x

D
x/4

Solution
Question 10
1 / -0

Positive deviation from ideal behaviour takes place because of :

A
molecular interaction between atoms and

B
molecular interaction between atoms and

C
finite size of atoms and

D
finite size of atoms and

Solution

A gas shows a positive deviation from ideal behaviour if there is a force between the molecules and repulsive force dominates over attractive force. For such gases the compressibility factor z is more than 1 or z