Coordination Compounds Test

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Coordination Compounds Test - 16

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Weekly Quiz Competition

Question 1
1 / -0

Only One Option Correct Type
Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Primary and secondary valency of Pt in [Pt(en)₂CI₂] are

A
+ 4 and - 4

B
+ 4 and 6

C
+ 6 and 4

D
+ 2 and 6

Solution

In [Pt(en)₂CI₂] the charge on the complex ion is +2 and coordination number is 6. Hence, the primary and secondary valency are +2 and 6 respectively.
Question 2
1 / -0

If zeise’s salt has the formula [Pt(C₂H₄)CI₃]^-. In this, platinum primary and secondary valency are

A
+ 1 and 3

B
+ 2 and 4

C
+ 3 and 4

D
+ 4 and 6

Solution

Let the oxidation state of pt be x.
Oxidation state of cl is -1.
So x + 0 – (1*3) must be equal to -1 since the charge of the whole compound is -1.
x + 0 – (1*3) = -1
x -3 = -1
x = -1 + 3
x = +2
So the oxidation state of platinum is +2.
Secondary is due to legend there are mono deadened legend
then 1×4= 4
Question 3
1 / -0

The two complexes PtCI₄. 2NH₃ and PtCI₄. 2KCI do not give precipitate of AgCI when treate with AgNO₃. The structures of these complexes are

A
[Pt(NH₃)₂CI₄] and K₂[PtCI₆]

B
[Pt(NH₃)₂] Cl₄ and K₂[PtCI₆]

C
[Pt(NH₃)₂CI₂]Cl₂ and K₂[PtCI₄]CI₂

D
[Pt(NH₃)₂CI₄] and K₂[PtCI₅]CI

Solution

Pt(NH₃)₂CI₄] is neutral complex and no ions are formed in aqueous solution.
K,(PtCl₆] → 2K⁺ + [PtCI₆]^2-
It does not have Cl^- ion toffive precipitate of AgCI.
Question 4
1 / -0

A cobaltamine has the formula CoCI₃ . xNH₃. This when reacted with AgNO₃ solution, one third of the chloride is precipitated. It can have the structure

A
[Co(NH₃)₆]CI₃

B
[Co(NH₃)₅]CI₂

C
[Co(NH₃)₄CI₂]CI

D
[Co(NH₃)₅H₂O]CI₃

Solution

Total chlorine molecules are 3 and one third means one chlorine molecule precipitates. So, one chlorine has to be outside the coordination sphere and that is in option C.
Question 5
1 / -0

Which is the incorrect ?

A
[Co(NH₃)₄CI₂]⁺ is heteroleptic complex

B
In [Fe(C₂O₄)₃]³⁺ and [Co(en)₃]³⁺, the coordination number of both Fe and Co is 6

C
Ferric alum is a double salt

D
Mohr’s salt is a double salt and do not give test for Fe²⁺ions

Solution

Mohr's salt is a doub le salt and it will give test for Fe²⁺ ion. It dissociates into simple substances or ions completely when dissolved in water.
Question 6
1 / -0

The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)₆ is

A
0

B
2.84

C
4.90

D
5.92

Solution

Cr(24) = [Ar]3d54s1
Since (CO) is strong ligand, in Cr(CO)6 none of the electron is unpaired. Therefore ‘spin only’ magnetic moment is zero.
Question 7
1 / -0

The anion acetylacetonate (acac) forms chelate with Co³⁺, The ring of the chelate is

A
five membered

B
four membered

C
six membered

D
three membered

Solution

The acetylacetonate (acac) forms six membered ring as follows:
Question 8
1 / -0

Oxidation states of iron in the complexes [Fe(H₂O)₅NO]²⁺ and [Fe(CN)₅NO]^2- are

A
+ 1 and + 2

B
+ 1 and + 1

C
+ 2 and + 2

D
+ 2 and + 1

Solution

Correct Answer : a
Explanation : NO in brown ring complex has +1 oxidation state.
Let oxidation state of Fe be x.
Since the overall charge on the coordination sphere, [Fe(H2O)5NO+] is +2, the sum of oxidation states of all elements in it should be equal to +2.
Therefore, x+1=+2
or, x=+1
Hence, the oxidation state of iron in the brown ring complex is +1.

[Fe(H2O)5NO+]2- iron is assigned an oxidation state of 2+. The iron center has a diamagnetic low-spin d6 electron configuration, although a paramagnetic long-lived metastable state has been observed by EPR spectroscopy. The chemical reactions of sodium nitroprusside are mainly associated with the NO ligand.
Question 9
1 / -0

Complexes in which the oxidation number of a metal is zero is/are

A
Cr(C₆H₆)₂

B
[Mn(CN)₆]^4-

C
[Ni(CO)₄]

D
All of these

Solution

In [Ni(CO)₄]
Let the oxidation state of Ni is x.
x + 4 x (0) = 0 (Carbonyl (CO) is a neutral ligand and have zero charge.)
x = 0
Hence, Ni have zero oxidation state.
Question 10
1 / -0

An example for bidentate and negatively charged ligand is

A
acetylacetonate (acac)

B
propylene diamine (pn)

C
ethylene diamine (en)

D
bipyridyl (bip

Solution

CH₃COCH₂COCH₃
It can ligate through two oxygen atoms.

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Coordination Compounds Test - 16

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Coordination Compounds Test - 16

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Question 1

+ 4 and - 4

+ 4 and 6

+ 6 and 4

+ 2 and 6

Solution

Question 2

+ 1 and 3

+ 2 and 4

+ 3 and 4

+ 4 and 6

Solution

Question 3

[Pt(NH3)2CI4] and K2[PtCI6]

[Pt(NH3)2] Cl4 and K2[PtCI6]

[Pt(NH3)2CI2]Cl2 and K2[PtCI4]CI2

[Pt(NH3)2CI4] and K2[PtCI5]CI

Solution

Question 4

[Co(NH3)6]CI3

[Co(NH3)5]CI2

[Co(NH3)4CI2]CI

[Co(NH3)5H2O]CI3

Solution

Question 5

[Co(NH3)4CI2]+ is heteroleptic complex

In [Fe(C2O4)3]3+ and [Co(en)3]3+, the coordination number of both Fe and Co is 6

Ferric alum is a double salt

Mohr’s salt is a double salt and do not give test for Fe2+ ions

Solution

Question 6

0

2.84

4.90

5.92

Solution

Question 7

five membered

four membered

six membered

three membered

Solution

Question 8

+ 1 and + 2

+ 1 and + 1

+ 2 and + 2

+ 2 and + 1

Solution

Question 9

Cr(C6H6)2

[Mn(CN)6]4-

[Ni(CO)4]

All of these

Solution

Question 10

acetylacetonate (acac)

propylene diamine (pn)

ethylene diamine (en)

bipyridyl (bip

Solution

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[Pt(NH₃)₂CI₄] and K₂[PtCI₆]

[Pt(NH₃)₂] Cl₄ and K₂[PtCI₆]

[Pt(NH₃)₂CI₂]Cl₂ and K₂[PtCI₄]CI₂

[Pt(NH₃)₂CI₄] and K₂[PtCI₅]CI

[Co(NH₃)₆]CI₃

[Co(NH₃)₅]CI₂

[Co(NH₃)₄CI₂]CI

[Co(NH₃)₅H₂O]CI₃

[Co(NH₃)₄CI₂]⁺ is heteroleptic complex

In [Fe(C₂O₄)₃]³⁺ and [Co(en)₃]³⁺, the coordination number of both Fe and Co is 6

Mohr’s salt is a double salt and do not give test for Fe²⁺ions

Cr(C₆H₆)₂

[Mn(CN)₆]^4-

[Ni(CO)₄]