Chemical Bonding and Molecular Structure Test

Result

Chemical Bonding and Molecular Structure Test - 5

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Weekly Quiz Competition

Question 1
1 / -0

Which atom, when bonded to hydrogens, will not be sp³ hybridized at the central carbon?

A
B

B
C

C
N

D
O

Solution

Boron forms BH₃, which is trigonal planar – the boron is sp² hybridized.
Question 2
1 / -0

Which of the following statements are correct-

1) Bond order of NO =2.5

2) Bond order of NO⁺ =1

3) Bond order of CO₃^2- =1.75

4) Bond order of O₂ =2

A
1, 2

B
2, 3, 4

C
1, 4, 3

D
1, 4

Solution

NO has (7+8) 15 electrons, and having bond order of 2.5 [as that of O₂⁺ having 15 electrons]

bond order of O₂ is 1/2 [10-6] =2
Question 3
1 / -0

Which one of the following has the strongest O-O bond?

A
O₂⁺

B
O₂

C
O₂^-

D
O₂^2-

Solution

bond order of O₂⁺ is 1/2 [10-5] =2.5

bond order of O₂ is 1/2 [10-6] =2

bond order of O₂^- is 1/2 [10-7] =1.5

Bond order of O₂^2- is 1/2 [10-8] =1

Higher the bond order higher the bond dissociation energy and stronger the bond.

Among all, O₂⁺ has strongest bond.
Question 4
1 / -0

If geometry is linear, trigonal planar and tetrahedral then unhybridized p orbital will have values?

A
2, 1, 0

B
1, 1, 0

C
1, 2, 0

D
1, 1, 2

Solution

The unhybridized p atomic orbitals are used to form π bonds. Two unhybridized p atomic orbitals each from a different atom overlap side to side, resulting in a shared electron pair occupying the space above and below the line joining the atoms (the internuclear axis).