Chemical Bonding and Molecular Structure Test 11

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Chemical Bonding and Molecular Structure Test 11

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Question 1
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Direction (Q. Nos. 1-14) This section contains 14 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.
Q. Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B₂ is
[IIT JEE 2010]

A
1 and diamagnetic

B
0 and diamagnetic

C
1 and paramagnetic

D
0 and paramagnetic

Solution

B₂ (10 electrons)
MO electronic configuration is
Bonding electrons = 6
Anti-bonding electrons = 4

No unpaired electron-diamagnetic
Question 2
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In which of the following pairs of molecules/ions both the species are not likely to exist?

A

B

C

D

Solution

Species with (zero) bond order will not exist.
Electrons in orbital
Question 3
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Among the following the maximum covalent character is shown by the compound

A
MgCl₂

B
FeCl₂

C
SnCl₂

D
AlCl₃
Question 4
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Assuming (2s-2p) mixing is not operative, the paramagnetic species among the following is
[JEE Advanced 2014]

A
Be₂

B
B₂

C
C₂

D
N₂

Solution

If (2s-2p) mixing is not operative, then
Question 5
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Select the correct statem ent about and and O₂.

A
and O₂ both are paramagnetic and bond order of is greater than that O₂

B
is paramagnetic and O₂ is diamagnetic and bond order of is greater than that o f O₂

C
is paramagnetic and O₂ is diamagnetic and bond order of is less than that of O₂

D
None of the above is correct

Solution
Question 6
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The common features among the species CN^-, CO, NO⁺ and N₂ are

A
isoelectronic, paramagnetic, bond order three

B
isoelectronic, diamagnetic, bond order three

C
isoelectronic, paramagnetic, bond order two

D
isoelectronic, diamagnetic, bond order two

Solution

Thus, all these are isoelectronic. MO electronic configuration is
No electron unpaired - diamagnetic
Bonding electrons = 10
Anti-bonding electrons = 4
Thus, bond- order =
Question 7
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According to MO theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

A

B

C

D

Solution
Question 8
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O — F and F₂ can be compared in terms of

A
OF is paramagnetic while F₂ is diamagnetic

B
OF is more stable towards dissociation into atoms

C
Both the above are correct

D
None of the above is correct

Solution

Bond energy of O — F (1.5) > F — F (1)
Thus, OF is more stable than F₂ thus, (c).
Question 9
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Which of the following diatomic molecules would be stabilised by the removed of an electron?

A
C₂

B
CN

C
N₂

D
O₂

Solution

A molecule is stabilised if bond-order increases, an anti-bonding electron is lost
Question 10
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Probability (electron charge density) of bonding and anti-bonding molecular orbitals are given.
Select the correct probability,

A
I bonding, II anti-bonding

B
II bonding, I anti-bonding

C
Both I and II bonding

D
Both I and II anti-bonding

Solution

Electron-charge density in a bonding molecular orbital is high in the internuclear region as shown in II.
In an anti-bonding molecular orbital, it is high in parts of the molecule away from the internuclear region.
Question 11
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If one of the electrons in the He₂ molecule is taken to the next excited state, then bond order in He₂

A
increases by 1 unit

B
decreases by 1 unit

C
increases by 0.5 unit

D
no change

Solution

Electron is taken to next excited state that is hen electronic configuration is

Number of electrons in bonding molecular orbital = 3
and in anti-bonding molecular orbital = 1
Thus, bond order = (3 - 1) /2 =1
Thus, bond order increases by 1 unit.
Question 12
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If one of the electrons (1s²) of helium is taken in excited state then bond order of He₂ is

A
0 (zero)

B
1

C
0.5

D
2.0

Solution

Number of electrons in bonding orbital = 4 and in anti-bonding orbitai = 0
Question 13
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The bond energy of H₂ is 436 kJ mol ^-1. Thus, bond energy of is

A
436 kJ mol ^-1

B
218 kJ mol^-1

C
327 kJ mol^-1

D
872 kJ mol^-1

Solution
Question 14
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Consider the following oxidation/reduction process,

Q. Magnetic moment does not change in

A
I

B
II

C
Ill

D
IV

Solution
Question 15
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Direction (Q. Nos. 15) This sectionis based on statement I and Statement II. Select the correct answer from the code given below.
Q.
Statement I : N₂ has a greater dissociation energy than , where as O₂ has lower dissociation energy than .
Statement II : N₂ has 14 electrons while O₂ has 16 electrons .

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

Electron from bonding molecular orbital of higher stability is lost (requires higher energy).

Electron from antibonding molecular orbital of lower stability is lost (requires lower energy).
N₂ has 14 electrons and O₂ has 16 electrons.
Thus, both Statements I and II are correct but Statement II is not the correct explanation of Statement I