Ionic Equilibrium Test

Result

Ionic Equilibrium Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

The pH of blood does not appreciably change by a small addition of an acid or a base because blood

A
contains serum protein which acts as a buffer

B
contains iron as a part of the molecule

C
can be easily coagulated

D
is a body fluid

Solution

pH of blood does not change because it acts as a buffer.
Question 2
1 / -0

What is the maximum concentration of equimolar solution of ferrous sulphate and sodium sulphide, so that when mixed in equal volumes there is no precipitation of iron sulphide? [K_sp for iron sulphide = 6.3 × 10^-18]

A
4 × 10^-9mol L^-1

B
4.8 × 10^-11mol L^-1

C
5.02 × 10^-9mol L^-1

D
6 × 10^-9mol L^-1

Solution

Let the concentration of FeSO₄ and Na₂S be x mol L^-1.
Then, after mixing equal volumes:
[FeSO₄] = [Na₂S] = x/2 M
Or [Fe²⁺] = [S^2-] = x/2 M
FeS ⇌ Fe²⁺ + S²
K_sp = [Fe²⁺][S^2-]
6.3 × 10^-18 = (x/2)(x/2)
On solving, x = 5.02 × 10^-9 mol L^-1

The maximum concentration of equimolar solution of ferrous sulphate and sodium sulphide, so that when mixed in equal volumes there is no precipitation of iron sulphide is 5.02 × 10^-9 mol L^-1.
Question 3
1 / -0

For a sparingly soluble salt A_pB_q, the relationship between its solubility product (L_s) and its solubility (S) is

A
L_s = S^p+qp^p q^q

B
L_s = S^p+q p^q q^p

C
L_s= S^pq p^p q^p

D
L_s = S^pq (pq)^q+p

Solution

A_pB_q = pA⁺ + qB^-
If S is the solubility,
[A⁺] = pS, [B^-] = qS;
K_sp = [A⁺]^p[B^-]^q
L_s= (pS)^p (qS)^q = S^p+qp^p q^q