Solutions Test ...

Only One Option Correct Type
This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct

Q.

The degree of dissociation (α ) o f weak electrolyte A_xB_y is related to van’t Hoff factor (i) by the expression

[AIEEE 2011]

0.004 M Na₂S0₄ aqueous solution is isotonic with 0.01 M glucose solution at 300 K. Thus, degree of dissociation of Na₂S0₄ is

When 20 g of naphthoic acid (C₁₁H₈O₂) is dissolved in 50 g of benzene, a freezing point depression of 2 K is observed. [K_f (benzene) = 1.72Kmol^-1 kg]. The van’t Hoff factor (i) is 

[IIT - JEE 2007]

An aqueous solution of a solute AB has boiling point of 101.08° C and freezes at -1 .80 °C . AB is found to be 100% ionised at boiling point. If K_b /K_f = 0.3, then AB

Osmolarity of 0.02 M potassium ferrocyanide solution at 300 K is (assume solute is 100% ionised)

AB and CD are two non -volatile solutes dissolved in same solvent, showing following behaviour

AB is ionised in solvent, α = degree of ionisation

CD is dimerised in solvent, 3 = degree of dimerisation

If α = 0.80, then β is

Which has the highest boiling point?