S-Block Elements Test

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S-Block Elements Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

Be is not readily attacked by acids because:

A
It is less reactive.

B
Of formation of protective oxide layer on the surface.

C
Of formation of protective chloride layer on the surface.

D
It is stable.

Solution

Due to the formation of a protective oxide layer on the surface of Be, its reactivity with acids decreases.
Question 2
1 / -0

Be can show coordination number four while other members show a value of six. This is because of:

A
Small size of Be

B
Availability of d orbitals in Be

C
Non availability of d orbitals in Be

D
High ionization enthalpy of Be

Solution

The electronic configuration of Be is 1s²2s². We can see that there are only 4 orbitals in its valence shell( they are s and p). In other words, d orbital is absent. So, Be shows ccoordination no 4 and not 6 as like other members of its group.
Question 3
1 / -0

Be and Al compounds are largely covalent because of:

A
Low charge density

B
High ionization enthalpy

C
Low ionization enthalpy

D
High charge density

Solution

Be and Al compounds are largely covalent because of high charge density leading to high polarizing power of the cations.
Question 4
1 / -0

Li and Mg both form chlorides which are:

A
Highly ionic

B
Unstable

C
Alkaline

D
Deliquescent

Solution

Chlorides of both Li and Mg are deliquescent (absorb moisture from surroundings) and soluble in alcohol and pyridine. Lithium chloride, like magnesium chloride (MgCl₂.6H₂O) separates out from hydrated crystal LiCl.2H₂O.
Question 5
1 / -0

Li shows difference in properties than rest of the members of its group but shows similarities with:

A
Mg

B
Al

C
Ca

D
Be

Solution

Due to diagonal relationship, Li resembles Mg.
Question 6
1 / -0

Be shows difference in properties as compared to rest of the members of its group because of:

A
Small size

B
High ionization enthalpy

C
Non availablilty of d orbitals

D
All the above

Solution

Be shows anomalous behaviour because of small size, high ionization enthalpy and non availablilty of d orbitals.
Question 7
1 / -0

Be and Al form chlorides which are:

A
Arrhenius acids

B
Bronsted Lowry acids

C
Lewis acids

D
Lewis bases

Solution

Be and Al forms compound with Cl as BeCl
Question 8
1 / -0

Which of the following is a correct statement?

A
LiNO₃ on decomposition forms LiNO₂ while NaNO₃ forms NaNO₂

B
LiNO₃ on decomposition forms Li NO₂ while NaNO₃ forms NaO₂

C
LiNO₃ on decomposition forms Li₂O while NaNO₃ forms NaNO₂

D
LiNO₃ on decomposition forms Li₂O while NaNO₃ forms NaO₂
Question 9
1 / -0

Name the element which forms the stable fluoro complex anions:

A
Ba

B
Sr

C
Ca

D
Be

Solution

Fluorine forms molecules with fourteen metals because its small size and single charge as an ion allows surrounding metal atoms with more fluorines than oxygen.
Question 10
1 / -0

Which of the following is amphoteric?

A
BeO

B
MgO

C
CaO

D
All the above

Solution

BeO is amphoteric as it can react with both acids and base
BeO₊₂NaOH = Na₂BeO₂
BeO+H₂SO₄ + BeSO₄ + H₂O
On the other hand, MgO and Cao are metallic oxides and act as a base only.

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S-Block Elements Test - 11

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S-Block Elements Test - 11

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Question 1

It is less reactive.

Of formation of protective oxide layer on the surface.

Of formation of protective chloride layer on the surface.

It is stable.

Solution

Question 2

Small size of Be

Availability of d orbitals in Be

Non availability of d orbitals in Be

High ionization enthalpy of Be

Solution

Question 3

Low charge density

High ionization enthalpy

Low ionization enthalpy

High charge density

Solution

Question 4

Highly ionic

Unstable

Alkaline

Deliquescent

Solution

Question 5

Mg

Al

Ca

Be

Solution

Question 6

Small size

High ionization enthalpy

Non availablilty of d orbitals

All the above

Solution

Question 7

Arrhenius acids

Bronsted Lowry acids

Lewis acids

Lewis bases

Solution

Question 8

LiNO3 on decomposition forms LiNO2 while NaNO3 forms NaNO2

LiNO3 on decomposition forms Li NO2 while NaNO3 forms NaO2

LiNO3 on decomposition forms Li2O while NaNO3 forms NaNO2

LiNO3 on decomposition forms Li2O while NaNO3 forms NaO2

Question 9

Ba

Sr

Ca

Be

Solution

Question 10

BeO

MgO

CaO

All the above

Solution

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LiNO₃ on decomposition forms LiNO₂ while NaNO₃ forms NaNO₂

LiNO₃ on decomposition forms Li NO₂ while NaNO₃ forms NaO₂

LiNO₃ on decomposition forms Li₂O while NaNO₃ forms NaNO₂

LiNO₃ on decomposition forms Li₂O while NaNO₃ forms NaO₂