p-Block Elements Test

Result

p-Block Elements Test - 28

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Weekly Quiz Competition

Question 1
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Direction (Q. Nos. 1- 10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.
Q.
Regarding the properties of hydrogen halides, which is wrong order?

A
Melting point order HI> HF > HBr > HCI

B
Boiling point order HF > HI > HBr > HC

C
Acidic nature HI > HBr > HCI > HF

D
Percentage of ionic character HF > HI > HBr > HCI

Solution

The correct order of % of ionic character is
Question 2
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The reaction 3ClO^-(aq) → 2Cl^- (aq) + ClO₃^-(aq) is an example of

A
oxidation reaction

B
reduction reaction

C
disproportionation reaction

D
decomposition reaction

Solution

The reaction in which a species is simultaneously reduced and oxidised to form two different products is known as disproportionation reaction.
Question 3
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Which is incorrect statement?

A
The stability of oxides formed by l > Br > Cl

B
Fluorine forms only one oxoacid while other halogens form different oxoacids

C
I₂O₅ is very good oxidising agent and used in the estimation of CO

D
CIO₂ is used as a bleaching agent for paper pulp and textiles

Solution

As we move down the group, stability of oxides decreases because the size increases.
Question 4
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When gold and platinum dissolves in aqua-regia, the complexes formed are

A

B

C

D

Solution
Question 5
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Mixture which contains equal amount of sodium chloride (NaCl) and sodium chlorate (NaClO₃) gives off

A
bleach

B
aerosols

C
solvents

D
refrigerants

Solution

The correct answer is option A
On decomposition of NaClO₃ , it gives NaCl and O in nascent form. it might get decomposed. As we know nascent [O] shows bleaching action due to its oxidizing properties.
Question 6
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In perchloric acid (HCIO₄), the number of σ and π-bonds

A
5σ and 4π-bonds

B
6σ and 3π-bonds

C
5σ and 3π-bonds

D
5σ and 2π-bonds

Solution

The structure of perchlo ric acid (HCIO₄) is

5σ and 3π-bonds
Question 7
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The correct order of acidic strength is

A
Cl₂O₇ > SO₂ > P₄O₁₀

B
SO₂ > Cl₂O₇ > P₄O₁₀

C
P₄O₁₀ > SO₂ > Cl₂O₇

D
N₂O₅ > P₄O₁₀ > SO₂

Solution

The correct order of acidic strength is Cl₂O₇ > SO₂ > P₄O₁₀
Question 8
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Which of the following arrangements gives the correct order of increasing oxidation number of iodine?

A
I₂ < HI < ICI < HIO₄

B
HI < ICI < I₂ < HIO₄

C
ICI < HI < HIO₄< I₂

D
HI < I₂< ICI < HIO₄

Solution
Question 9
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Which of the following is incorrect?

A

B

C
Cl₂O₇ is most acidic oxide

D
CIO^- is strong conjugate base

Solution

has pyramidal while has trigonal planar shape.
Question 10
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Correct order of bond angles are in

A
H₂O > OF₂ > Cl₂O > CIO₂

B
CIO₂ > Cl₂O > H₂O > OF₂

C
OF₂ > H₂O > Cl₂O > ClO₂

D
OF₂ > OCI₂ > H₂O > CIO₂

Solution

In CIO₂, due to larger size of chlorine atom, repulsion between non-bonding electrons on the chlorine atoms overcome the lone pair-lone pair repulsion. Hence, the order of bond angle
CIO₂ > Cl₂O > H₂O > OF₂
Question 11
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Direction (Q. Nos. 11-13) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.
Q.
Match the Column I with Column II and mark the correct option from the codes given below.

A

B

C

D

Solution
Question 12
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Match the Column I with Column II and mark the correct option from the codes given below.

A

B

C

D

Solution
Question 13
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Match the Column I with Column II and mark the correct option from the codes given below.

A

B

C

D

Solution
Question 14
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Direction : This section is based on Statement I and Statement II. Select the correct answer from the codes given below.
Q.
Statement I : On dehydration with P₂O₅ at 263 K, HCIO₄ gives Cl₂O₇.
Statement II : This method is used in the preparation of Cl₂O₇

A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I

B
Both Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I

C
Statement I is correct but Statement II is incorrect

D
Statement II is correct but Statement I is incorrect

Solution

On dehydration with P₂O₅ at - 10°C, HCIO₄ gives Cl₂O₇ which is the anhydride of perchloric acid.

This reaction has been used for the preparation of Cl₂O₇.