p-Block Elements Test

Result

p-Block Elements Test - 35

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Weekly Quiz Competition

Question 1
1 / -0

Nitrogen shows different oxidation states ranging from

A
-3 to +5

B
-5 to +5

C
-0 to -5

D
-3 to +3

Solution

Nitrogen shows different oxidation states ranging from -3 to +5 in its compound
Question 2
1 / -0

The oxidation state of nitrogen is highest in:

A
N₃H

B
NH₃

C
NH₂OH

D
N₂H₄

Solution

O.S. of N in N₃H = -1/3
O.S.of N in NH₃ = -3
O.S. of N in NH₂OH = -1
O.S. of N in NH₂H₄ = -2
Question 3
1 / -0

Which of the following shows nitrogen with its increasing order of oxidation number?

A
N₂O < NO < NO₂ < NO^-₃ < NH⁺₄

B
NH₄⁺ < N₂O < NO < NO₂ < NO^-₃

C
NH₄⁺ < N₂O < NO < NO₂ < NO^-₃

D
NH⁺₄ < NO < N₂O < NO₂ < NO^-₃

Solution

N2O = +1, NO = +2, NO2 = +4,= +5, = -3
increasing order of oxidation state will be
< N₂O < NO < NO₂ <
Question 4
1 / -0

Nitrogen forms stable N₂ molecule but phosphorus is converted to P₄ from P₂because:

A
pπ-pπ bonding is strong in phosphorus

B
pπ-pπ bonding is weak in phosphorus

C
Triple bond is present in phosphorus

D
Single P−P bond is weaker than N−N bond

Solution

pπ - pπ bonding in nitrogen is strong hence it can form triple bond with another N. Single N−N bond is weaker than P−P bond due to high interionic repulsion of non-bonding electrons. Hence, N=N is stable and P₂ is not.
Question 5
1 / -0

The decreasing order of boiling points of the following hydrides is:

A
H₂O > SbH₃ > AsH₃ > PH₃ > NH₃

B
H₂O > NH₃> SbH₃ > AsH₃ > PH₃

C
H₂O > SbH₃ > NH₃ > AsH₃ > PH₃

D
H₂O > PH₃ > AsH₃ > SbH₃ > NH₃

Solution

H₂O and NH₃ have abnormally high boiling boilling points of their tendency to form hydrogen bonds. NH₃ has hiigher boiling point than phosphine and then boiling pont increase down the group because of increase in size . Hence the order of boiling point will be
H₂O > SbH₃ > NH₃ > AsH₃ > PH₃