p-Block Elements Test

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p-Block Elements Test - 44

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Weekly Quiz Competition

Question 1
1 / -0

Which compound is prepared by the following reaction?

A
XeF₄

B
XeF₂

C
XeF₆

D
None of these.

Solution
Question 2
1 / -0

Which of the following statements is not correct about XeF₂?

A
It can be obtained by direct reaction between F₂ and Xe at high pressure

B
XeF₂ undergoes alkaline hydrolysis to give O₂ and Xe

C
XeF₂ is a powerful reducing agent

D
XeF₂ contains two bond pairs and three lone pairs

Solution

XeF₂ is obtained by direct reaction of Xe and F₂ at high pressure. It undergoes alkali hydrolysis to produce Xe and O₂. XeF₂is a powerful reducing agent where Xe+2 can change to +6 state.
Question 3
1 / -0

Complete the following reactions by filling the appropriate choice.
(A) 6XeF₄ + 12H₂O → 4Xe + 2XeO₃ + _(i)_ + _(ii)_
(B) XeF₆ + 3H₂O → _(iii)_ + 6HF

A
(i) F₂, (ii) H₂O, (iii) XeOF₄

B
(i) 24HF, (ii) 3O₂, (iii) XeO₃

C
(i) 2HF, (ii) 2H₂O, (iii) XeO

D
(i) HF, (ii) H₂O, (iii) Xe₂O₃

Solution

Balance chemical equation for the above two reactions are:
(A) 6XeF₄ + 12H₂O ⟶ 4Xe + 2XeO₃+ 24HF + 3O₂
(B) XeF₆ + 3H₂O ⟶ XeO₃ + 6HF
So, (i) = 24HF; (ii) = 3O₂ and (iii) = XeO₃
Question 4
1 / -0

Among the following molecules:
(i) XeO₃ (ii) XeOF₄ (iii) XeF₆
those having same number of lone pairs on Xe are:

A
(i) and (ii) only

B
(i) and (iii) only

C
(ii) and (iii) only

D
(i), (ii) and (iii)

Solution
Question 5
1 / -0

Match the column I with column II and mark the appropriate choice.

A
(A) → (i); (B) → (ii); (C) → (iii); (D) → (iv)

B
(A) → (iv); (B) → (iii); (C) → (ii); (D) → (i)

C
(A) → (iii); (B) → (iv); (C) → (i); (D) → (ii)

D
(A) → (ii); (B) → (iii); (C) → (iv); (D) → (i)

Solution

Hybridization of an atom is identified by caliculating the sum of sigma bonds and lone pairs.
If sum of sigma bonds and lone pairs is 2. sp hybridization
If sum of sigma bonds and lone pairs is 3. sp² hybridization
If sum of sigma bonds and lone pairs is 4. sp³ hybridization.XeO₃ has 3 sigma bonds and 1 lone pair.So the sum is 4.So it is sp³
If sum of sigma bonds and lone pairs is 5. sp³d hybridization.XeOF₂has 3 sigma bonds and two lone pairs ,the sum is 5.So it is SP³d.
If sum of sigma bonds and lone pairs is 6 .sp³d² hybridization.XeF₄ has 4 sigma bonds and 2 lone pair.So the sum is 6.So it is sp³d²
If sum of sigma bonds and lone pairs is 7. sp³d² hybridization.XeF₆ has 6 sigma bonds and 1 lone pair. So the sum is 7.So it is sp³d³
So the option A is correct match.
Question 6
1 / -0

In XeF₂, XeF₄, and XeF₆, the number of lone pairs on Xe, is respectively.

A
2,3,1

B
1,2,3

C
4,1,2

D
3,2,1

Solution

XeF₂ has a linear shape. Its hybridization is sp³d which means it should have a trigonal bipyramidal shape. Since it has 3 lone pairs, they occupy the equatorial triangle.
XeF₄ has sp³d² hybridization. It has a square planar shape and 2 lone pair of electrons.
XeF₆ has one lone pair of electrons. The 6 out of 8 electrons of Xenon are shared by 6 atoms of fluorine.
Question 7
1 / -0

Which of the following is not correct about xenon hexafluoride?

A
It has oxidation state of +6

B
The hybridisation involved in XeF₆ is sp³d³

C
The shape of XeF₆ is distorted octahedral and can be represented as

D
On hydrolysis it gives Xe, HF and O₂

Solution

On hydrolysis the products formed are XeO₃ and HF.
XeF₆ + 3H₂O → XeO₃ + 6HF
Question 8
1 / -0

Which of the following is not a use of noble gases?

A
Argon is widely used for filling incandescent electric bulbs

B
Neon is used in safety devices for protecting electrical instruments

C
Radon is used in radiotherapy of cancer

D
Helium is filled in tubes of cycles and scooters tyres

Solution

Helium is used in filling tubes of aeroplane tyres.
Question 9
1 / -0

Which of the following statements is not correct?

A
Helium has the lowest boiling point among the noble gases

B
Argon is used in electric bulbs

C
Krypton is obtained during radioactive disintegration

D
Xe forms XeF₆

Solution

Air is also the most important source for the other noble gases.T races of krypton are found in various minerals, the most important source of Krypton is Earth's atmosphere. Helium obtained from natural gas and radon is obtained as a byproduct during radioactive disintegration.
So Rn is obtained during radioactive disintegration not Kr.
So Krypton is obtained during radioactive disintegration is the wrong statement.
Question 10
1 / -0

Compound with the geometry square pyramidal and sp³d² hybridisation is:

A
XeOF₂

B
XeOF₄

C
XeO₄

D
XeO₂F₂

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p-Block Elements Test - 44

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p-Block Elements Test - 44

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Question 1

XeF4

XeF2

XeF6

None of these.

Solution

Question 2

It can be obtained by direct reaction between F2 and Xe at high pressure

XeF2​ undergoes alkaline hydrolysis to give O2​ and Xe

XeF2 is a powerful reducing agent

XeF2 contains two bond pairs and three lone pairs

Solution

Question 3

(i) F2​, (ii) H2​O, (iii) XeOF4​

(i) 24HF, (ii) 3O2​, (iii) XeO3​

(i) 2HF, (ii) 2H2​O, (iii) XeO

(i) HF, (ii) H2​O, (iii) Xe2​O3​

Solution

Question 4

(i) and (ii) only

(i) and (iii) only

(ii) and (iii) only

(i), (ii) and (iii)

Solution

Question 5

(A) → (i); (B) → (ii); (C) → (iii); (D) → (iv)

(A) → (iv); (B) → (iii); (C) → (ii); (D) → (i)

(A) → (iii); (B) → (iv); (C) → (i); (D) → (ii)

(A) → (ii); (B) → (iii); (C) → (iv); (D) → (i)

Solution

Question 6

2,3,1

1,2,3

4,1,2

3,2,1

Solution

Question 7

It has oxidation state of +6

The hybridisation involved in XeF6 is sp3d3

The shape of XeF6 is distorted octahedral and can be represented as

On hydrolysis it gives Xe, HF and O2

Solution

Question 8

Argon is widely used for filling incandescent electric bulbs

Neon is used in safety devices for protecting electrical instruments

Radon is used in radiotherapy of cancer

Helium is filled in tubes of cycles and scooters tyres

Solution

Question 9

Helium has the lowest boiling point among the noble gases

Argon is used in electric bulbs

Krypton is obtained during radioactive disintegration

Xe forms XeF6​

Solution

Question 10

XeOF2​

XeOF4​

XeO4​

XeO2​F2​

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XeF₄

XeF₂

XeF₆

It can be obtained by direct reaction between F₂ and Xe at high pressure

XeF₂ undergoes alkaline hydrolysis to give O₂ and Xe

XeF₂ is a powerful reducing agent

XeF₂ contains two bond pairs and three lone pairs

(i) F₂, (ii) H₂O, (iii) XeOF₄

(i) 24HF, (ii) 3O₂, (iii) XeO₃

(i) 2HF, (ii) 2H₂O, (iii) XeO

(i) HF, (ii) H₂O, (iii) Xe₂O₃

The hybridisation involved in XeF₆ is sp³d³

The shape of XeF₆ is distorted octahedral and can be represented as

On hydrolysis it gives Xe, HF and O₂

Xe forms XeF₆

XeOF₂

XeOF₄

XeO₄

XeO₂F₂