p-Block Elements Test

Result

p-Block Elements Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the most acidic?

A
P₂O₃

B
Sb₂O₃

C
Bi₂O₃

D
As₂O₃

Solution

Acidic character of group 15 oxides decreases down the group. This is because acidic strength of the oxides decreases with decrease in the electronegativity of the element.
Hence, among the given options, P₂O₃ is the most acidic.
Question 2
1 / -0

In earlier days of photography, strong ammonia solution was used to dissolve unchanged AgBr. In photographic 'fixing', nowadays, ammonia has been replaced by Na₂S₂O₃ because

A
Na₂S₂O₃ is a solid and is easy to handle as compared to ammonia

B
Na₂S₂O₃ is cheaper than ammonia

C
Na₂S₂O₃gives better quality pictures than ammonia

D
ammonia is harmful and unpleasant to the photographer in confined space of darkroom

Solution

This is the proper reason as ammonia is very harmful and intolerable in a closed space.
Question 3
1 / -0

Directions For Questions

The following question has four choices, out of which ONLY ONE is correct.

...view full instructions

Which of the following statements about SCl₄ is not correct?

A
It is a stable solid.

B
It has a trigonal bipyramidal structure with one of the equatorial positions occupied by a lone pair of electrons.

C
S-Cl bond distances in equatorial and axial positions are 155 pm and 165 pm, respectively.

D
Cl-S-Cl bond angles in equatorial and axial planes are 102⁰ and 172⁰,respectively.

Solution

Wrong. SCl₄ is an unstable liquid.
Question 4
1 / -0

The most favourable condition for the manufacture of NH₃ is

A
high temperature and high pressure

B
low temperature and low pressure

C
high temperature and low pressure

D
low temperature and high pressure

Solution

Manufacturing of ammonia is done by Haber process. The most favourable condition for Haber process is low temperature and high pressure.
Question 5
1 / -0

The oxidation state of nitrogen in dinitrogen oxide is

A
+ 1

B
+ 2

C
+ 3

D
+ 4

Solution

Dinitrogen oxide, N₂O
2x + (-2) = 0
So, x = +1
Question 6
1 / -0

A gas X with disagreeable odour reduces silver nitrate solution to give metallic silver and is itself oxidised to Y. Y is a dibasic acid with reducing properties. It is slowly oxidised in air to a tribasic acid Z. Though Z is a tribasic acid, it behaves in aqueous solution mostly as a dibasic acid. When a mixture of X and N₂O is subjected to electric spark, Z is obtained.

The gas X is

A
ammonia

B
phosphine

C
hydrogen sulphide

D
sulphur dioxide

Solution

Phosphine is a gas with disagreeable odour of rotten fish. It can reduce silver nitrate solution to metallic silver and is itself oxidised to H₃PO₃, a dibasic acid with reducing properties.
6AgNO₃ + PH₃ + 3H₂O → 6Ag + H₃PO₃ + 6HNO₃
Question 7
1 / -0

Which of the following statements is incorrect regarding hypophosphorous acid?

A
It is a dibasic acid.

B
It contains P in +1 oxidation state.

C
It is a strong reducing agent.

D
It is obtained during the preparation of phosphine from white phosphorus.

Solution

This is wrong. There is only one replaceable hydrogen atom in hypophosphorous acid; so it is a monobasic acid.
Question 8
1 / -0

Which of the following is the strongest acid?

A
HClO₄

B
HNO₃

C
HClO

D
H₂SO₄

Solution

The oxidation state of the central atom in this case is +7, which is the highest of the given options. Hence, it is the strongest acid among all.

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Re-Attempt Weekly Quiz Competition

p-Block Elements Test - 13

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p-Block Elements Test - 13

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Question 1

P2O3

Sb2O3

Bi2O3

As2O3

Solution

Question 2

Na2S2O3 is a solid and is easy to handle as compared to ammonia

Na2S2O3 is cheaper than ammonia

Na2S2O3 gives better quality pictures than ammonia

ammonia is harmful and unpleasant to the photographer in confined space of darkroom

Solution

Question 3

It is a stable solid.

It has a trigonal bipyramidal structure with one of the equatorial positions occupied by a lone pair of electrons.

S-Cl bond distances in equatorial and axial positions are 155 pm and 165 pm, respectively.

Cl-S-Cl bond angles in equatorial and axial planes are 1020 and 1720, respectively.

Solution

Question 4

high temperature and high pressure

low temperature and low pressure

high temperature and low pressure

low temperature and high pressure

Solution

Question 5

+ 1

+ 2

+ 3

+ 4

Solution

Question 6

ammonia

phosphine

hydrogen sulphide

sulphur dioxide

Solution

Question 7

It is a dibasic acid.

It contains P in +1 oxidation state.

It is a strong reducing agent.

It is obtained during the preparation of phosphine from white phosphorus.

Solution

Question 8

HClO4

HNO3

HClO

H2SO4

Solution

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P₂O₃

Sb₂O₃

Bi₂O₃

As₂O₃

Na₂S₂O₃ is a solid and is easy to handle as compared to ammonia

Na₂S₂O₃ is cheaper than ammonia

Na₂S₂O₃gives better quality pictures than ammonia

Cl-S-Cl bond angles in equatorial and axial planes are 102⁰ and 172⁰,respectively.

HClO₄

HNO₃

H₂SO₄