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p-Block Elements Test - 18

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p-Block Elements Test - 18
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Weekly Quiz Competition
  • Question 1
    1 / -0

    The oxidation state of sulphur in anions SO32-, S2O42- and S2O62- follows the order

    Solution

    O.S. of S in SO32- = (+ 4), that in S2O42- = (+3) and that in S2O62- = (+ 5).

     

  • Question 2
    1 / -0

    The main reaction involved in the manufacture of sulphuric acid is:

    2SO2 (g) + O2 (g) → 2SO3 (g); ΔH = -98 kJ

    According to Le Chatelier's principle, the quantity of SO3 (g) can be increased when

    Solution

    In order to get as much sulphur trioxide as possible in the equilibrium mixture, we need as high a pressure as possible. High pressures also increase the rate of the reaction.

     

  • Question 3
    1 / -0

    Which of the following are the peroxides of sulphur?

    A. H2S2O3
    B. H2S2O8
    C. H2SO5
    D. H2SO3

    Solution

    Peroxydisulphuric acid (H2S2O8) and Peroxymonosulphuric acid (H2SO5) are peroxides of sulphur.

     

  • Question 4
    1 / -0

    Which of the following orders is not correct for halogens?

    A. Ionic radius (X-): F- < Br- < Cl-
    B. Electron gain enthalpy (-ve): F > Br > Cl
    C. Ionisation enthalpy: F > Cl > Br
    D. Melting point (K): F2 < Cl2 < Br2

    Solution

    B and C are incorrect because negative electron gain enthalpy decreases in the order Cl > F > Br > I and ionic radius increases in the order F- < Cl- < Br-.

     

  • Question 5
    1 / -0

    Aqueous solution of Na2S2O3 on reaction with Cl2 gives

    Solution

    Na2S2O3 shows reducing action as it is oxidized by chlorine.
    Na2S2O3 + 4Cl2 + 5H2O → 2NaHSO4 + 8HCl

     

  • Question 6
    1 / -0

    Choose the incorrect statement.

    Solution

    HCl is a stronger acid than HF.

     

  • Question 7
    1 / -0

    Which of the following is the correct order of stability of interhalogen compounds?

    Solution

    Stability of interhalogen compounds increases with increase in electronegativity difference between halogens. So, the order is IF3 > BrF3 > ClF3.

     

  • Question 8
    1 / -0

    XeF4 reacts with water at – 80oC to give

    Solution

    XeF4 + H2O → XeOF2 + 2HF

     

  • Question 9
    1 / -0

    The formation of O2+[PtF6]- is the basis for the formation of xenon fluoride. This is because

    Solution

    The first ionization enthalpy of xenon (1170 kJ mol-1) is quite close to that of dioxygen (1175 kJ mol-1).

     

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