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p-Block Elements Test - 22

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p-Block Elements Test - 22
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  • Question 1
    1 / -0

    Which among the following compound, nitrogen shows the oxidation state of +5?

    Solution

    N has +5 in HNO3. Oxidation state of O is -2 and H is +1.​

  • Question 2
    1 / -0

    Which among the following forms basic oxide?

    Solution

    As we move down the group metallic character increases so Bi is a metal thus its oxide is basic.

  • Question 3
    1 / -0

    In laboratory ammonia is prepared by heating

    Solution

    2(NH4Cl) + Ca(OH)2 → (CaCl)2 + 2(NH3) + 2(H2O)
    Hence C is correct.

  • Question 4
    1 / -0

    Ammonia has a higher boiling point and is less volatile because of

    Solution

    NH3 undergo intermolecular hydrogen bonding and therefore it has higher boiling point compared to other hydrides of group 15.

  • Question 5
    1 / -0

    Which compound is used as the cooling liquid in refrigerators?

    Solution

    NH3  is used as cooling liquid in refrigerators.

  • Question 6
    1 / -0

    At what temperature white phosphorous changes to red phosphorous?

    Solution

    White phosphorus when heated to 300° C polymerization occurs and it changes to Red Phosphorus.

  • Question 7
    1 / -0

      is the structure of

    Solution

    H3PO2  is Hypophosphorus acid

  • Question 8
    1 / -0

    Elements of which group are known as ore forming elements?

    Solution

    Maximum ores are of group 16 elemnts (O, S etc).

  • Question 9
    1 / -0

    Most metal oxides are

    Solution

    Metal oxides are basic and ionic in nature.

  • Question 10
    1 / -0

    The stability of hydrides of group 16 elements decreases in the order

    Solution

    As we move down the group bond length increases therefore stability of hydrides decreases. Order of bond length O-H < S-H < Se-H < Te-H.

  • Question 11
    1 / -0

    Formula of oleum is

    Solution

    Oleum is H2S2O7

  • Question 12
    1 / -0

    Which among the following does not exhibit positive oxidation state?

    Solution

    Fluorine is most electronegative element therefore can only gain electrons. Thus it only shows negative oxidation state.

  • Question 13
    1 / -0

    Which of the following is the strongest Lewis base?

    Solution

    Correct Answer :- D

    Explanation : Lewis bases need to be able to donate electrons. Fluorine is the most electronegative element in the halogens followed by chlorine, bromine and iodine. 

    Due to fluorine being strongly electronegative, it draws the electron density towards itself which makes it difficult for nitrogen atom to donate its lone pair of electrons. So, NF is the least basic. This trend follows the strength of electronegativity of the halides. 

    Since iodine is least electronegative, it is the most basic trihalide of nitrogen.

    So, we have the trend, in decreasing order of basic strength:

    NF3 < NCl3 < NBr3 < NI3

  • Question 14
    1 / -0

    Hydrogen sulphide reacts with lead acetate forming a black compound which reacts with hydrogen peroxide to form another compound. The colour of the compound is

    Solution

    PbS + H2O2 → PbSo4(white) + H2O

  • Question 15
    1 / -0

    Which of the following is thermally the most stable?

    Solution

     

    Stability of hydrides decreases down the group so most stable is H2O  

  • Question 16
    1 / -0

    Which of the following is prepared by cyanamide process?

    Solution

    CaNCN + 3H2O → CaCO3 + 2NH3

  • Question 17
    1 / -0

    Ozone can be detected by using

    Solution

    Ozone is detected by using Hg.

  • Question 18
    1 / -0

    Which of the following oxides reacts with both HCl and NaOH?

    Solution

    ZnO is an amphroteric oxide.

  • Question 19
    1 / -0

    Name the gas whose formula was established by Sorret?

    Solution

    Sorret established formula of ozone.

  • Question 20
    1 / -0

    Which colour is given by CuSO4 with ammonia?

    Solution

    Cu2+  + 4NH3 → [Cu (NH3)4]2+ (blue)

  • Question 21
    1 / -0

    Xenondifluoride is

    Solution

    CN = 0.5(V+M-C+A) For XeF2 CN = 5 so shape will be linear and structure will be trigonal pyramidal.

  • Question 22
    1 / -0

    A metal X on heating in nitrogen gas gives Y. Y on treatment with water gives a colourless gas which when passed through copper sulphate solution gives a blue colour. Y is

    Solution

    Mg3N2 reacts with water to evolve NH3. Which reacts with copper ion to form blue color complex.

  • Question 23
    1 / -0

    The reagent used to distinguish between H2O2 and O3 is:

    Solution

    H2O2 can decolorize the color of KMnO4

  • Question 24
    1 / -0

    When chlorine is passed through concentrated hot solution of KOH, the compound formed is

    Solution

     

    Cl2 on treatment with conc. Base form ClO3-

  • Question 25
    1 / -0

    Ammonia can be dried using

    Solution

    CaO is used to dry NH3

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