Atomic Structure Test

Result

Atomic Structure Test - 25

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.
Q. Which is a possible set of quantum numbers for a valence unpaired electrons in ground state atom of phosphorus (Z = 15)?

A

B

C

D

Solution

Valence unpaired electrons are in 3p

Valence unpaired electrons are in 3p.

Thus, (d).
Question 2
1 / -0

For a multi-electron atom, set of quantum numbers is given as
2,0,0,1/2 ; 2,0,0,-1/2
Q. Thus, the next higher allowed set of n and / quantum numbers for this atom in its ground state is

A
n=3, l=0

B
n=3, l=1

C
n=2, l=0

D
n=2, l=1

Solution

Given a set of quantum numbers, n=2,l=0 for a multi-electron atom refers to 2s orbital.
The next higher allowed set of 'n' and 'l' quantum numbers for this atom in the ground state is n=2,l=1. This corresponds to 2p orbital.
Note: The orbital with a higher value of the sum (n+l) has higher energy.
For 2s orbital (n+l)=(2+0)=2
For 2p orbital (n+l)=(2+1)=3
Question 3
1 / -0

Magnetic moments of the following isoelectronic species (24 electrons) are in order

A

B

C

D

Solution
Question 4
1 / -0

The orbital angular momentum for a d-orbital electron is given by

A

B

C

D

Solution
Question 5
1 / -0

The number of radial nodes in 3s and 2p respectively are

A
2 and 0

B
0 and 2

C
1 and 2

D
2 and 1

Solution

Radial nodes = (n - l - 1)
Angular nodes = l, total nodes = (n - 1), nodal plane = l
Question 6
1 / -0

A hydrogen like species in fourth orbit has radius 1.5 times that of Bohr's orbit. In neutral state, its valence electron is in

A
1s

B
2p

C
3s

D
3d

Solution
Question 7
1 / -0

Following suborbits with values of n and l are given
Q. Increasing order of energy of these suborbits is

A
IV < III < II < I

B
IV < III < I < II

C
IV < II < III < I

D
I < III < II < IV

Solution

By Aufbau rule, smaller the value of (n + I), smaller the energy. If (n + I) is same for two or more orbits, suborbit with lower value of n, has smaller energy.
Question 8
1 / -0

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is
[JEE Main 2013]

A

B

C

D

Solution
Question 9
1 / -0

For Cr(24), (EC) : [Ar] 4s¹ 3d⁵ The number of electrons with l = 1 to l = 2 are respectively

A
12 and 4

B
12 and 5

C
16 and 4

D
16 and 5

Solution

EC of Cr (24) is
Question 10
1 / -0

Last filling electron in lanthanides find place in 4f-orbital. Which of the following sets of quantum number is correct for an electron in 4f orbital?

A

B

C

D

Solution

4l -orbital
Thus, n = 4, l = 3
m, (anyone) = - 3, - 2, - 1, 0, +1, + 2, + 3
Question 11
1 / -0

Quantum Numbers are solutions of _____________

A
Heisenberg’s Uncertainty Principle

B
Einstein’s mass energy relation

C
Schrodinger’s Wave Equation

D
Hamiltonian Operator

Solution

When the wave function for an atom is solved using the Schrodinger Wave Equation, the solutions obtained are called the Quantum Number which are basically n, l and m.
Question 12
1 / -0

Which quantum numbers gives the shell to which the electron belongs?

A
m

B
n

C
l

D
s

Solution

The principal quantum number, n, gives the shell to which the electron belongs. The energy of the shell is dependent on ‘n’.
Question 13
1 / -0

Direction (Q. Nos. 18) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.
Q. Match the entries in Column I with correctly related quantum number(s) in Column II

A
a

B
b

C
c

D
d

Solution

(i) Orbital angular momentum L =
L depends on the value of l (azimuthal quantum number)
(ii) To describe wave function (), n, I and m are needed, if, it obeys Pauli's exclusion principle, then s is also needed.
(iii) Value of n, I and m are needed to determine size, shape and orientation.
(iv) Probability density (²) is based on n, I and m