Atomic Structure Test

Result

Atomic Structure Test - 26

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Weekly Quiz Competition

Question 1
1 / -0

The ratio of charge to mass of an electron in coulombs per gram was determined by J.J. Thomson. He determined this ratio by measuring the deflection of cathode rays in electric and magnetic fields. What value did he find for this ratio?

A
-1.76 x 10⁸ coulombs/g

B
1.76 x 10^-8 coulombs/g

C
-1.76 x 10¹⁰ coulombs/g

D
- 1.76 x 10^-10 coulombs/g

Solution

Charge of an electron is
= −1.6 × 10⁻¹⁹C
Mass of electron is
9.1 × 10⁻³¹kg = 9.1 × 10⁻²⁸g
Thus, Charge/mass ratio is

= −1.76 × 10⁸ coulombs /g
Question 2
1 / -0

The number of electrons which will together weigh one gram is

A
1.098 x 10²⁷ electrons

B
9.1096 x 10³¹ electrons

C
1 electron

D
1 x 10⁴ electrons

Solution

Mass of electron = 9.1096 x 10^-31 kg

= 1.098 x 10²⁷ electrons
Question 3
1 / -0

How many number of electrons are present in a particle which carries a charge of 5.5 x 10^-16 C?

A
3432

B
1560

C
8240

D
2432

Solution

Charge carried by one electron
= 1.6022 x 10^-19 C
Electrons presents in 5.5 x 10^-16 C
Question 4
1 / -0

Which experiment is responsible for finding out the charge on an electron?

A
Millikan’s oil drop experiment

B
Cathode ray discharge tube experiment

C
Rutherford’s α-rays scattering experiment

D
Photoelectric experiment

Solution

The value (magnitude) of electron charge was determined by Millikan's oil drop experiment.
Cathode ray discharge tube experiment gave the sign of electron charge Rutherford's experiment gave the presence of electrons around the dense nucleus
Photoelectric experiment explained the production of electricity from light irradiation on the metal surface.
Question 5
1 / -0

Match the values of column II with column I and mark the appropriate choice.

A
(A)→(i),(B)→(ii),(C)→(iv),(D)→(iii)

B
(A)→(iii),(B)→(i),(C)→(ii),(D)→(iv)

C
(A)→(ii),(B)→(iii),(C)→(iv),(D)→(i)

D
(A)→(i),(B)→(iii),(C)→(ii),(D)→(iv)

Solution

(A) Mass of electron = 9.1 × 10⁻³¹ Kg
(B) Mass of proton = 1.673 × 10⁻²⁷ kg
(C) Charge of electron = −1.602 × 10⁻¹⁹ C
(D) e/m for an electron = 1.76 × 10⁸ C/g
Thus option B is the correct answer.