Chemistry Test 100

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Chemistry Test 100

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Weekly Quiz Competition

Question 1
4 / -1

Solid Ba(NO₃)₂ is gradually dissolved in 1.0 × 10^–4 M Na₂CO₃ solution. At which concentration of Ba²⁺ the precipition will begin? (K_sp BaCO₃ = 5.1 × 10^–9)

A
4.1 × 10^–5 M

B
5.1 × 10^–5 M

C
8.1 × 10^–8 M

D
8.1 × 10^–7 M
Question 2
4 / -1

Which of the following mixture of solution can function as a buffer solution ?

A
50 ml of 0.1 M CH₃COOH + 50 ml of 0.1 M NaOH

B
50 ml of 0.2 M HCl + 50 ml of 0.2M NaOH

C
50 ml of 0.2 M NH₃ + 50 ml of 0.2M HCl

D
50 ml of 0.2 M NH₃ + 50 ml of 0.1M HCl
Question 3
4 / -1

20 mL, 5M NaNO₂ solution is mixed with 100 mL, 2M HNO₂ solution to prepare a buffer solution of pH = 5.7. The K_a of HNO₂ is-

A
10^–6

B
10^–5

C
4 × 10^–6

D
4 × 10^–5

Solution
Question 4
4 / -1

The pK_a for acid A is greater than pK_a for acid B. The strong acid is :-

A
B

B
A

C
Both A and B

D
Neither A nor B
Question 5
4 / -1

For the reaction A + B → Products

it is observed that

(a) On doubling the initial concentration of A only the rate of reaction is also double and

(b) On doubling the concentration of both A and B there is a change by a Factor of 8 in the rate of the reaction then the rate of this reaction is given by

A
rate = K [A] [B]

B
rate = K [A]² [B]

C
rate = K [A] [B]²

D
rate = K [A]² [B]²
Question 6
4 / -1

In the reaction :

A + 2B + C → D + 2E

The rate of formation of D remains unchanged if the concentration of B is doubled and that of A and C is kept constant. What is the order with respect to B ?

A
0

B
1/2

C
1

D
3
Question 7
4 / -1

The decomposition of azomethane at certain temperature according to the equation (CH₃)₂N₂ → C₂H₆ + N₂ is a first order reaction. After 40 minutes from the start the total pressure developed is found to be 350 mm of Hg in place on initial pressure 200 mm of Hg of azomethane. The value of rate constant K is :-

A
2.88 × 10^–4 sec^–1

B
1.25 × 10^–4 sec^–1

C
5.77 × 10^–4 sec^–1

D
None of these
Question 8
4 / -1

Given that K is the rate constant for some order of any reaction at temperature T then the value of log K.

A

B
A

C
2.303 A

D
log A

Solution
Question 9
4 / -1

Consider the following equilibrium in a closed container , N₂O₄(g) 2NO₂(g). At a fixed temperature, If inert gas is mixed. Which of the following statements holds true regarding the equilibrium constant (K_p) and degree of dissociation (α) :-

A
Neither K_p nor α changes

B
Both K_p and α changes

C
K_p changes but α does not

D
K_p does not change but α changes
Question 10
4 / -1

At 87°C the following equilibrium is established. H_2(g) + S_(s) H₂S_(g) ; K_p = 7×10^–2

If 0.50 mole of Hydrogen and 1.0 mole of sulphur are heated to 87°C in 1.0 L vessel, what will be the partial Pressure of H₂S at equilibrium when P_T = 1 atm :-

A
0.065 atm

B
1.38 atm

C
0.0327 atm

D
1 atm

Solution

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Chemistry Test 100

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Chemistry Test 100

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Question 1

4.1 × 10–5 M

5.1 × 10–5 M

8.1 × 10–8 M

8.1 × 10–7 M

Question 2

50 ml of 0.1 M CH3COOH + 50 ml of 0.1 M NaOH

50 ml of 0.2 M HCl + 50 ml of 0.2M NaOH

50 ml of 0.2 M NH3 + 50 ml of 0.2M HCl

50 ml of 0.2 M NH3 + 50 ml of 0.1M HCl

Question 3

10–6

10–5

4 × 10–6

4 × 10–5

Solution

Question 4

B

A

Both A and B

Neither A nor B

Question 5

rate = K [A] [B]

rate = K [A]2 [B]

rate = K [A] [B]2

rate = K [A]2 [B]2

Question 6

0

1/2

1

3

Question 7

2.88 × 10–4 sec–1

1.25 × 10–4 sec–1

5.77 × 10–4 sec–1

None of these

Question 8

A

2.303 A

log A

Solution

Question 9

Neither Kp nor α changes

Both Kp and α changes

Kp changes but α does not

Kp does not change but α changes

Question 10

0.065 atm

1.38 atm

0.0327 atm

1 atm

Solution

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4.1 × 10^–5 M

5.1 × 10^–5 M

8.1 × 10^–8 M

8.1 × 10^–7 M

50 ml of 0.1 M CH₃COOH + 50 ml of 0.1 M NaOH

50 ml of 0.2 M NH₃ + 50 ml of 0.2M HCl

50 ml of 0.2 M NH₃ + 50 ml of 0.1M HCl

10^–6

10^–5

4 × 10^–6

4 × 10^–5

rate = K [A]² [B]

rate = K [A] [B]²

rate = K [A]² [B]²

2.88 × 10^–4 sec^–1

1.25 × 10^–4 sec^–1

5.77 × 10^–4 sec^–1

Neither K_p nor α changes

Both K_p and α changes

K_p changes but α does not

K_p does not change but α changes