Self Studies

Chemistry Test 101

Result Self Studies

Chemistry Test 101
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    How much iron will be obtained by reduction of 1 kg of Fe2O3 according to this reaction :-

    Fe2O3 + 3H2 → 2Fe + 3H2O

  • Question 2
    4 / -1

    The total number of neutrons present in 54 ml H2O(ℓ) are :-

  • Question 3
    4 / -1

    Actual mass of hydrogen molecule is approximately:-

  • Question 4
    4 / -1

    A compound was found to contain nitrogen and oxygen in the ratio 28:80. The empirical formula of compound is :-

    Solution

     

  • Question 5
    4 / -1

    If 0.5 mol of CaBr2 is mixed with 0.2 mol of K3PO4, the maximum number of moles of Ca3(PO4)2 that can be formed is :

    3CaBr2 + 2K3PO4 → Ca3(PO4)2 + 6KBr

    Solution

    3CaBr2 +  2K3PO4 —→  6KBr   + Ca3(PO4)2

    3 mol           2 mol      6 mol     1 mol

    According to the chemical reaction,

    2 mol of K3PO4 reacts = 3 mol of CaBr2

    0.2 mol of K3PO4 reacts = 0.3 mol of CaBr2

    Moles of CaBr2 left unreacted = 0.5 – 0.3 = 0.2

    Hence, K3PO4 is the limiting reagent, since it reacts completely and it decides the amount of products, thus formed

    2 mol of K3PO4 gives = 1 mol of Ca3(PO4)2

    0.2 mol of K3PO4 gives = 0.1 mol of Ca3(PO4)2

     

  • Question 6
    4 / -1

    What volume of oxygen gas measured at 0°C and 1 atm is needed to burn completely 2L butane (C4H10) under same conditions ?

    Solution

     

  • Question 7
    4 / -1

    How many litres of air are required to burn 5L methane ? (Air contains O2 20% by volume) :-

  • Question 8
    4 / -1

    10 moles of CH4 combines with 18 moles of oxygen. Calculate the moles of CO2 formed after combustion :-

    Solution

     10        9
    CH4 + 2O2 → CO2 + 2H2O
    10       18
    ∴ L.R. is O2 ⇒ 18/2 = 9 (minimum)
    O2     CO2
    2         1
    18       X
    2x = 18 ⇒ x = 9 moles of CO2 is formed

     

  • Question 9
    4 / -1

    For reaction A + 2B → C. The amount of product formed by starting the reaction with 5 mole A and 8 mole B is :-

    Solution

     

  • Question 10
    4 / -1

    Which and what amount will remain unreacted after the reaction between 3g carbon and 2g oxygen to produce CO.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now