Chemistry Test 124

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Chemistry Test 124

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Weekly Quiz Competition

Question 1
4 / -1

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be :-

A
1 mol

B
2 mol

C
3 mol

D
4 mol

Solution

2H₂ + O₂ → 2H₂O

(5 mole) (2 mole)

L.R.
Question 2
4 / -1

How much oxygen is required for complete combustion of 560 g of ethene ?

A
6.4 kg

B
1.92 kg

C
2.8 kg

D
9.6 kg

Solution
Question 3
4 / -1

If 20% nitrogen is present in a compound its minimum molecular weight will be :

A
144

B
28

C
100

D
70

Solution
Question 4
4 / -1

Potential energy of electron present in He⁺ is :-

A

B

C

D

Solution
Question 5
4 / -1

40% of a mixture of 0.2 mole of N₂ and 0.6 mole of H₂ react to give NH₃ according to the equation, N₂(g) + 3H₂(g) 2NH₃(g) at constant temperature and pressure. Then ratio of the final volume to the initial volume of gases are :-

A
4 : 5

B
5 : 4

C
7 : 10

D
8 : 5

Solution

at constant temperature and pressure volume of gas ∝ moles

N₂(g) + 3H₂(g) 2NH₃(g)

0.2 0.6 0

0.2 – 0.08 0.6 – 0.24 0.16

= 0.12 = 0.36 =0.16
Question 6
4 / -1

Which of the following salt will not under go hydrolysis :

A
NH₄Cl

B
KCl

C
NaCN

D
Na₂CO₃

Solution

Salt of SASB will not under go hydrolysis
Question 7
4 / -1

K_C for A(g) + B(g) C(g) + D(g) is 10 at 25°C. If a container contains 1,2,3,4 mol/litre of A,B,C and D respectively at 25°C, the reaction will proceed:-

A
From left to right

B
From right to left

C
in Equilibrium

D
Either of these

Solution

A(g) + B(g) C(g) + D(g) ; K_C = 10
1 2 3 4
So K_C(10) > Q(6)
So reaction will proceed from left to right
Question 8
4 / -1

When 1 mole of a gas is heated at constant volume, temperature is raised from 298 to 308 K. Heat supplied to gas is 500 J. Then which statement is correct ?

A
q = W = 500 J; ΔU = 0

B
q = ΔU = 500 J; W = 0

C
q = W = 500 J; ΔU = 500 J

D
ΔU = 0, q = W = –500 J

Solution

Volume remains constant so W = 0

q = ΔU = +500J
Question 9
4 / -1

Directions For Questions

Based on following thermo chemical reaction

   H₂O(g) + C(s) → CO(g) + H₂(g); ΔH = 131 kJ

   CO(g) + 1/2 O₂ (g) → CO₂(g) ; ΔH = –282 kJ

   H₂(g) + 1/2 O₂ (g) → H₂O(g) ; ΔH = –242 kJ

   C(s) + O₂(g) → CO₂(g) ; ΔH = x kJ

...view full instructions

The value of x will be

A
–393 kJ

B
–655 kJ

C
+393 kJ

D
+655 kJ

Solution

Using Hess law,

R_f = R₁ + R₂ + R₃

ΔH_f = ΔH₁ + ΔH₂ + ΔH₃

x = 131 + (–282) + (–242)

[x = –393 kJ ]
Question 10
4 / -1

For the reaction; 3X(g) + Y(g) X₃Y(g), the amount of X₃Y at equilibrium is affected by :-

A
Temperature and pressure

B
Pressure only

C
Temperature only

D
Temperature, pressure and catalyst

Solution

Equilibrium concentration changes with P and T.