Chemistry Test 131

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Chemistry Test 131

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Weekly Quiz Competition

Question 1
4 / -1

The correct oreder of increasing bond angles in the following species

A
Cl₂O < ClO₂ < ClO₂^-

B
ClO₂ < Cl₂O < ClO₂^-

C
Cl₂O < ClO₂^- < ClO₂

D
ClO₂^- < ClO₂ < Cl₂O

Solution

According to VESPR theory repulsion order

lp - lp > lp - bp > bp - bp

As the number of lone pairs of electrons increases, bond angle decreases due to repulsion between lp-lp, Moreover, as the electronegativity of central atom decreases, bond angle decreases.

The correct order of increasing bond angle is Cl₂O < ClO₂^- < ClO₂

In ClO₂^- there are 2 Ione pairs of electrons present on the central chlorine atom. Therefore the bond angle in ClO₂^-is less than 118° which is the bond angle in ClO₂ which has less number of electrons on chlorine.
Question 2
4 / -1

The correct order of increasing covalent character of the following is

A
SiCl₄ < AlCl₂ < CaCl₂ < KCl

B
KCl < CaCl₂ < AlCl₃ < SiCl₄

C
AlCl₃< CaCl₂ < KCl < SiCl₄

D
None of these

Solution

Option b is correct because as the charge increases covalent character also increases.
Question 3
4 / -1

If Z-axis is the molecular axis, then π molecular orbitals are formed by the overlap of

A
s + p_z

B
P_x + P_y

C
P_z + Pz

D
P_x + P_x

Solution

p_x-p_x and p_y-p_y will form pi bond when z-axis is molecular axis as the options have only one of these so option (d) is the correct answer.
Question 4
4 / -1

The ionic species having largest size is

A
Li⁺ (g)

B
Na⁺ (aq)

C
Rb⁺ (aq)

D
Li⁺(aq)

Solution

Li⁺have larger size in aq.solution due to the presence of the water molecules present inside the solution surronds easily and become the solution to be more hydrated comparing to the corresponding element present in the aqeous solution.
Question 5
4 / -1

From the following species, which one is the easiest to remove one electron ?

A
O(g)

B
O^2-

C
O⁺

D
O^-

Solution

Ionisation Potential is directly proportional to positive oxidation state and inversely proportional to negative oxidation state.So, in O^2- removal of electron is easiest.
Question 6
4 / -1

Electron gain enthalpy of inert gases is

A
High

B
Low but positive

C
Moderate

D
Almost zero

Solution

On moving down the group, there is an increase in the size of atoms. As a result, the tendency to accept an additional electron decreases and hence, the electron gain enthalpy decreases from Ne to Rn. However, He has small size and much higher tendency to accept an additional electron. Hence, its electron gain enthalpy is least positive of all the noble gases.

Thus, it is concluded that neon has the highest positive electrons gain enthalpy.
Question 7
4 / -1

The electron gain enthalpies of B,C,N and O are in the order

A
B < C < N < O

B
B < C < O > N

C
B < C > O > N

D
B > C < O < N

Solution

Actually electron gain enthalphy and ionisation energy both are dependent on electronic configuration.

Electronegativity means tendency to attract electron it doesnot matter where it will keep the electron

Electron gain entalphy basically refer to attract e it must have space to keep electron in sub shell like spdf should be present order of electronegativity is

F > O > N > Cl > Br > I > S > C > P
Question 8
4 / -1

With respect to chlorine, hydrogen will be

A
Electropositive

B
Electronegative

C
Neutral

D
None of these

Solution

With respect to Chlorine hydrogen will be electropositive. Chlorine being a strong electronegative element tends to force hydrogen to loss electron and hydrogen acquire electropositive character so that chlorine can complete its octet .
Question 9
4 / -1

Which element has the greatest tendency to lose electrons ?

A
F

B
S

C
Fr

D
Be

Solution

Francium has the greatest tendency to lose electrons.
Question 10
4 / -1

Which of the following atomic numbers represents an alkali metals ?

A
37

B
55

C
87

D
All the three

Solution

37 = Rb

55 = Cs

87 = Fr

All belong to alkali metal group.

So answer is (d)

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Re-Attempt Weekly Quiz Competition

Chemistry Test 131

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Chemistry Test 131

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Question 1

Cl2O < ClO2 < ClO2-

ClO2 < Cl2O < ClO2-

Cl2O < ClO2- < ClO2

ClO2- < ClO2 < Cl2O

Solution

Question 2

SiCl4 < AlCl2 < CaCl2 < KCl

KCl < CaCl2 < AlCl3 < SiCl4

AlCl3< CaCl2 < KCl < SiCl4

None of these

Solution

Question 3

s + pz

Px + Py

Pz + Pz

Px + Px

Solution

Question 4

Li+ (g)

Na+ (aq)

Rb+ (aq)

Li+(aq)

Solution

Question 5

O(g)

O2-

O+

O-

Solution

Question 6

High

Low but positive

Moderate

Almost zero

Solution

Question 7

B < C < N < O

B < C < O > N

B < C > O > N

B > C < O < N

Solution

Question 8

Electropositive

Electronegative

Neutral

None of these

Solution

Question 9

F

S

Fr

Be

Solution

Question 10

37

55

87

All the three

Solution

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Cl₂O < ClO₂ < ClO₂^-

ClO₂ < Cl₂O < ClO₂^-

Cl₂O < ClO₂^- < ClO₂

ClO₂^- < ClO₂ < Cl₂O

SiCl₄ < AlCl₂ < CaCl₂ < KCl

KCl < CaCl₂ < AlCl₃ < SiCl₄

AlCl₃< CaCl₂ < KCl < SiCl₄

s + p_z

P_x + P_y

P_z + Pz

P_x + P_x

Li⁺ (g)

Na⁺ (aq)

Rb⁺ (aq)

Li⁺(aq)

O^2-

O⁺

O^-