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Chemistry Test 17

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Chemistry Test 17
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The redox reaction of Cu2O and Cu2S will give

    Solution

    2Cu2O(s) + Cu2S(s) →6Cu(s) + SO2 (g)

    In this reaction copper is reduced from +1 to zero oxidation state and sulphur is oxidised from -2 to +4 state.

  • Question 2
    4 / -1

    When potassium iodide, KI is mixed with a bromine solution. There is a colour change from an orange-brown to brown. This happen because of

    Solution

    Br2 is orange-brown in colour and it is reduced to Br- which is colourless. So, the reason for overall colour change goes to brown due to the oxidation of I-(colourless) to I2 (brown). 
    Half reaction: Br2 (aq) + 2e- → 2Br- (aq) 
    2I-(aq) →I2 (aq) + 2e- 
    Full reaction: Br2 (aq) +2I- (aq) → 2Br- (aq)+ I2 (aq)

  • Question 3
    4 / -1

    When sodium hydroxide added in chromium trioxide, the compound formed is

    Solution

    Chromium trioxide is an inorganic compound. Its formula is CrO3. It is the acidic anhydride of chromic acid. When CrO3 reacts with NaOH, sodium chromate and water are formed.

    CrO3 + 2NaOH → Na2CrO4 + H2O

  • Question 4
    4 / -1

    In Nessler’s reagent, the ion present is

    Solution

    Nessler’s reagent is Potassium tetraiodomercurate (II). The ions present in it are K+and HgI42-.

  • Question 5
    4 / -1

    Which of the following lanthanoid ions is diamagnetic ?

    (At nos. Ce = 58, Sm = 62, Eu = 63, Yb = 70)

    Solution

    Yb+2 is [Xe]4f14 .as no unpaired electron is present so diamagnetic.

  • Question 6
    4 / -1

    A magnetic moment of 1.73 BM will be shown:

    Solution

    In, [Cu (NH3)4]2+, Copper is in 2+ oxidation state, i.e, d9 configuration. It means it have one unpaired electron.

    Magnetic moment= √ (n (n+2) BM

    = √ (1(1+2) BM

    = 1.73 BM.

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