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Chemistry Test 174

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Chemistry Test 174
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  • Question 1
    4 / -1

    The outer orbitals of C in ethene molecule can be considered to be hybridized to give three equivalent sp² orbitals. The total number of sigma (s) and pi (p) bonds in ethene molecule is

    Solution

    According to valence bond theory, two atoms form a covalent bond through the overlap of individual half-filled valence atomic orbitals, each containing one unpaired electron. In ethene, each hydrogen atom has one unpaired electron and each carbon is sp² hybridized with one electron each sp² orbital. The fourth electron is in the p orbital that will form the pi bond. The bond order for ethene is simply the number of bonds between each atom: the carbon-carbon bond has a bond order of two, and each carbon-hydrogen bond has a bond order of one.

     

  • Question 2
    4 / -1

    Which of the following is a linear molecule?

    Solution

    The steric number of central atom of a linear molecule is two. It has two bonded atoms and zero lone pair. All the molecules have two bonded atoms. Thus, we need to work out the number of lone pairs.

    In ClO2, the central atom Cl has 7 valence electrons. Four are used up to form 4 bonds with O atoms. Three are non-bonding electrons. Thus, along with an odd electron, it has a lone pair.

    In CO2, the central C atom has 4 valence electrons. All are used up to form four bonds with O atoms. Thus, it has zero lone pair.

    In NO2, the central N atom has 5 valence electrons. Four are used up to form bonds with oxygen atoms. Thus, one electron is left as an odd electron.

    In SO2, the central S atom has 6 valence electrons. Four are used up to form bonds with oxygen atoms. Two nonbonding electrons form one lone pair.

     

  • Question 3
    4 / -1

    Which of the following will have the lowest boiling point?

    Solution

    Boiling point increases with increase in molecular mass. For the compounds with the same molecular mass, boiling point decreases with an increase in branching.

    The molecular mass of 2-Methylbutane: 72 g mol-1

    The molecular mass of 2-Methylpropane: 58 g mol-1

    The molecular mass of 2, 2-Dimethylpropane: 72 g mol-1

    The molecular mass of 2-Methylbutane: 72 g mol-1

    2-Methylpropane has the lowest molecular mass among all of the given compounds.

    Thus, 2-Methylpropane has the lowest boiling point among the given options.

     

  • Question 4
    4 / -1

    Among the following the maximum covalent character is shown by the compound

    Solution

    We know that, extent of polarisation ∝ covalent character in ionic bond. Fajans rule states that the polarising power of cation increases, with increase in magnitude of positive charge on the cation Therefore, polarising power ∝ charge of cation.

    The polarising power of cation increases with the decrease in the size of a cation. Therefore, polarising (power) ∝ (1)/ (size of cation)

    Here the AlCl3 is satisfying the above two conditions i.e., Al is in +3 oxidation state and also has small size. So it has more covalent character.

     

  • Question 5
    4 / -1

    An atom of an element A has three electrons in its outermost orbit and that of B has six electrons in its outermost orbit. The formula of the compound between these two will be

    Solution

    A has 3 electrons in outermost orbit and B has 6 electrons in its outermost orbits. So A can give three electrons to complete its octet and B needs 2 electrons to complete its octet. So 2 atoms of A will release 6 electrons and 3 atoms of B will need six electrons to complete their octet

    So, the formula will be A2​B3

     

  • Question 6
    4 / -1

    The bond length between hybridised carbon atom and other carbon atom is minimum in

    Solution

    The C – C bond length = 1.54 Å, C = C bond length = 1.34 Å and C ≡ C bond length = 1.20 Å.

    Since propyne has a triple bond, therefore it has minimum bond length.

     

  • Question 7
    4 / -1

    Which of the following reactions is a decomposition redox reaction?

    Solution

    Decomposition redox reaction leads to breakdown of a compound into two or more compounds at least one of which must be in the elemental state with change in oxidation number.

     

     

  • Question 8
    4 / -1

    What is the change in oxidation number of carbon in the following reaction?

    CH4(g) + 4Cl2(g) → CCl4(l) + 4HCl(g)

    Solution

    Change in oxidation state of carbon is from  − 4 to + 4.

     

     

  • Question 9
    4 / -1

    The correct option for a redox couple is:

    Solution

    Redox couple is both the reduced and oxidised form involve same element.

     

  • Question 10
    4 / -1

    Directions For Questions

    Which of the following reactions are disproportionation reaction?

    (a) 2Cu+ → Cu2+ + Cu0
    (b) 3MnO42+ + 4H+ → 2MnO4- + MnO2 + 2H2O
    (c) 2KMnO4 ⟶Δ K2MnO4 + MnO2 + O2
    (d) 2MnO4- + 3Mn2+ + 2H2O → 5MnO2 + 4H

    ...view full instructions

    Select the correct option from the following :

    Solution

    In a disproportionation reaction, same substance undergoes oxidation (increase in oxidation number) and reduction (decrease in oxidation number forming two different products.

     

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