Self Studies
Selfstudy
Selfstudy

Chemistry Test 198

Result Self Studies

Chemistry Test 198
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

    Identify the incorrect statement from the following.

    Solution

    In an atom, all the five 3d orbitals are equal in energy in free state i.e., degenerate.

    - The size of orbital depends on principal quantum number ' n ' therefore all the five 3d orbitals are different in size when compared to the respective 4d orbitals.

    - Shape of orbitals depends on azimuthal quantum number 'l' therefore shapes of 4d orbitals are similar to the respective 3d orbitals.

     

  • Question 2
    4 / -1

    Choose the correct answer from the options given below:

    Solution

    ℓ = 0 ⇒ s-subshell

    ℓ = 1 ⇒ p-subshell

    ℓ = 2 ⇒ d-subshell

    ℓ = 3 ⇒ f-subshell

    ∴ n = 2, ℓ = 1 ⇒2p

    n = 3, ℓ = 2 ⇒ 3d

    n = 3, ℓ = 0 ⇒ 3s

    n = 2, ℓ = 0 ⇒ 2s

     

  • Question 3
    4 / -1

    A particular station of All India Radio, New Delhi broadcasts on a frequency of 1,368 kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light c = 3.0 × 108 ms−1]

    Solution

     

  • Question 4
    4 / -1

    Which of the following series of transitions in the spectrum of hydrogen atom falls in visible region?

    Solution

    Lyman series : UV region

    Balmer series : Visible region

    Paschen series : IR region

    Brackett series : IR region

     

  • Question 5
    4 / -1

    In hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is

    [Given that Bohr radius, a0 = 52.9pm]

    Solution

    Bohr radius, a0 = 52.9pm

    n = 2, rn = n2a0 = (2)2a= 4 × 52.9pm = 211.6pm

    The angular momentum of an electron in a given stationary state can be expressed as in equation,

     

  • Question 6
    4 / -1

    Which one is the wrong statement?

    Solution

    In case of hydrogen like atoms, energy depends on the principal quantum number only. Hence, 2s -orbital will have energy equal to 2p -orbital.

     

  • Question 7
    4 / -1

    Which of the following pairs of d -orbitals will have electron density along the axes?

    Solution

     orbitals have electron density along the axes while dxy, dyz and dxz orbitals have electron density in between the axes.

     

  • Question 8
    4 / -1

    Which is the correct order of increasing energy of the listed orbitals in the atom of titanium

    (At. no. Z = 22)

    Solution

    Ti(22) = 1s22s22p63s23p64s23d2

    ∴ Order of increasing energy is 3s,3p,4s,3d

     

  • Question 9
    4 / -1

    The number of d-electrons in Fe2+(Z = 26) is not equal to the number of electrons in which one of the following?

    Solution

    The number of d-electrons in Fe²+ is calculated by considering the electron configuration of neutral iron (Fe), which is [Ar] 3d6 4s2. Upon losing two electrons to form Fe²+, the configuration becomes [Ar] 3d6. Therefore, Fe²+ has 6 d-electrons.

    • Option A: Neutral Fe has 6 d-electrons, which is equal to Fe²+'s d-electrons.
    • Option B: Ne has 6 p-electrons, which is equal to Fe²+'s d-electrons.
    • Option C: Mg has 2 s-electrons, which is not equal to Fe²+'s d-electrons.
    • Option D: Cl has 5 p-electrons, which is not equal to Fe²+'s d-electrons.

    Both options C and D have numbers of electrons that do not match the 6 d-electrons in Fe²+. However, since multiple-choice questions typically have one correct answer, option D is selected as it directly answers the question regarding p-electrons in Cl.

     

  • Question 10
    4 / -1

    Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)

    Solution

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now