Chemistry Test 206

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Chemistry Test 206

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Weekly Quiz Competition

Question 1
4 / -1

Based on the above equations, find out which of the relationship given below is correct.

A
z = x + y

B
x = y + z

C
y = 2z − x

D
x = y − z

Solution

According to Hess's law, equation (i) is equal to equations (ii) + (iii).
Question 2
4 / -1

Equal volumes of two monatomic gases, A and B at same temperature and pressure arc mixed. The ratio of specific heats (C_p/C_y) of the mixture will be

A
0.83

B
1.50

C
3.3

D
1.67

Solution

C_p for monoatomic gas mixture of same volume
Question 3
4 / -1

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is

A
10.52 cal/(mol K)

B
21.04 cal/(mol K)

C
5.260 cal/(mol K)

D
0.526 cal/(mol K)

Solution
Question 4
4 / -1

Enthalpy change for the reaction,

4H_(g) → 2H_2(g) is −869.6kJ

The dissociation energy of H - H bond is

A
- 434.8 kJ

B
- 896.6 kJ

C
+ 434.8 kJ

D
+ 217.4 kJ

Solution

The dissociation energy of H - H bond is 869.6/2 = 434.8 kJ
Question 5
4 / -1

Three moles of an ideal gas expanded spontaneously into vacuum. The work done will be

A
Infinite

B
3 Joules

C
9 Joules

D
Zero

Solution

Since the ideal gas expands spontaneously into vacuum,

P_ext= 0, hence work done is also zero.
Question 6
4 / -1

The electric charge for electrode deposition of one gram equivalent of a substance is:

A
96,500 coloumbs per second.

B
one ampere for one hour.

C
charge on one mole of electrons.

D
one ampere per second.

Solution

Charge of one mole of electrons = 96500C.

1 gram equivalent of substance will be deposited by one mole of electrons.

Charge of one mole of electrons = 96500 C = 96500 C.

11 grams equivalent of substance will be deposited by one mole of electrons.

1.602 × 10⁻¹⁹× 6.022 × 10²³≃ 96500 C

1 Faraday = 96500 C
Question 7
4 / -1

The charge in coulombs of 1 gram of ion N³⁻

A
0.688×10⁴ C

B
6.8 × 10⁴ C

C
20.6 × 10⁴ C

D
2.06 × 10⁴ C

Solution
Question 8
4 / -1

If a current of 0.50.5 ampere flows through a metallic wire for 2 h, then how many electrons would flow through the wire?

A
2.246 x 10²²

B
2.246 x 10^-22

C
2.246 x 10^-24

D
2.246 x 10²⁴

Solution

Quantity of charge (Q) passed = Current (C) x Time (t)

= (0.5 A) x (2 x 60 x 60 s) = 3600 C

Number of electrons flowing through the wire on passing a charge of one Faraday (96500 C) = 6.022 x 10²³

Number of electrons flowing the wire on passing a charge of
Question 9
4 / -1

Standard electrode potential for Sn⁴⁺/Sn²⁺ couple is +0.15 V and that for the Cr³⁺/Cr couple is −0.74 V. These two couples in their standard state are connected to make a cell. The potential will be:

A
+ 1.19 V

B
+ 0.89 V

C
+ 0.18 V

D
+ 1.83 V

Solution
Question 10
4 / -1

If the molar conductance value of Ca²⁺ and Cl⁻ at infinite dilution are respectively 118.88 × 10⁻⁴ m² mho mol⁻¹ and 77.33 × 10⁻⁴ m² mho mol⁻¹ then that of CaCl₂ is (in m² mho mol⁻¹ m² mho mol^-1)

A
118.88 × 10⁻⁴

B
154.66 × 10⁻⁴

C
273.54 × 10⁻⁴

D
196.21 × 10⁻⁴

Solution

According to Kohlrausch's law At infinite dilution molar conductivity is due to sum of all the cations and anions present in the solution

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Chemistry Test 206

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Chemistry Test 206

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Question 1

z = x + y

x = y + z

y = 2z − x

x = y − z

Solution

Question 2

0.83

1.50

3.3

1.67

Solution

Question 3

10.52 cal/(mol K)

21.04 cal/(mol K)

5.260 cal/(mol K)

0.526 cal/(mol K)

Solution

Question 4

- 434.8 kJ

- 896.6 kJ

+ 434.8 kJ

+ 217.4 kJ

Solution

Question 5

Infinite

3 Joules

9 Joules

Zero

Solution

Question 6

96,500 coloumbs per second.

one ampere for one hour.

charge on one mole of electrons.

one ampere per second.

Solution

Question 7

0.688×104 C

6.8 × 104 C

20.6 × 104 C

2.06 × 104 C

Solution

Question 8

2.246 x 1022

2.246 x 10-22

2.246 x 10-24

2.246 x 1024

Solution

Question 9

+ 1.19 V

+ 0.89 V

+ 0.18 V

+ 1.83 V

Solution

Question 10

118.88 × 10−4

154.66 × 10−4

273.54 × 10−4

196.21 × 10−4

Solution

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0.688×10⁴ C

6.8 × 10⁴ C

20.6 × 10⁴ C

2.06 × 10⁴ C

2.246 x 10²²

2.246 x 10^-22

2.246 x 10^-24

2.246 x 10²⁴

118.88 × 10⁻⁴

154.66 × 10⁻⁴

273.54 × 10⁻⁴

196.21 × 10⁻⁴