Chemistry Test 218

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Chemistry Test 218

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Weekly Quiz Competition

Question 1
4 / -1

The measurement of the electron position if associated with an uncertainty in momentum, which is equal to 1 × 10^–18 g cm s^{– 1} . The uncertainty in electron velocity is? (mass of an electron is 9 × 10^{– 28} g)

A
1 × 10⁹ cm s^–1

B
1 × 10⁶ cm s^–1

C
1 × 10⁵ cm s^–1

D
1 × 10¹¹ cm s^–1

Solution

Δp = mΔv Substituting the given values of Δx and m, we get 1×10^–18 gcms^–1 = 9×10^–28g × Δv
Question 2
4 / -1

Until what element was the Law of Octaves determined to be applicable?

A
Cobalt

B
Calcium

C
Potassium

D
Aluminium

Solution

The Law of Octaves was only valid up to the element calcium, because beyond calcium, every eighth element did not have properties that are identical to those of the first element.
Question 3
4 / -1

How many number of molecules and atoms respectively are present in 2.8 litres of a diatomic gas at STP?

A
6.023 x 10²³, 7.5 x 10²³

B
6.023 x 10²³, 15 x 10²²

C
7.5 x 10²², 15 x 10²²

D
15 x 10²², 7.5 x 10²³

Solution
Question 4
4 / -1

By Lewis structure NO has following fact

A

B
Bond order is 2.5 since, five electrons are shared between N and O-atom

C
There is one unpaired electron hence, NO is paramagnetic

D
All are correct facts

Solution
Question 5
4 / -1

Alkali metals are assigned which group in the Modern Periodic Table?

A
Second group

B
Eighteenth group

C
Third group

D
First group
Solution
- Group 1 elements in the Periodic table are known as Alkali metals
- They have ns1 outermost configuration and belong to the S-block Elements.
- They also have a strong tendency to donate their valence electrons in the outermost shell to form strong ionic bonds.
- It contains elements from Lithium (Li) to Francium (Fr).
Question 6
4 / -1

Among the following, the species having the smallest bond length is:

A
NO⁺

B
NO

C
O₂

D
NO^–

Solution

The bond order of given molecules are:

NO = 2.5, NO⁺ = 3, O₂ = 2, NO^– = 2

Larger the bond order, the smaller the bond length.

NO⁺ has the largest bond order 3.

Therefore, it will have the smallest bond length.

Hence option A is the answer.
Question 7
4 / -1

The elements with atomic numbers 35, 53 and 85 are _________.

A
noble gases

B
halides

C
alkaline

D
halogens

Solution
Question 8
4 / -1

Which of these belong to the same period?

Element A B C

Atomic number 2 10 5 respectively.

A
A, B

B
B, C

C
C, A

D
A, B and C
Solution
To determine which elements belong to the same period, we look at their atomic numbers and the corresponding periods:
- Element A (Atomic number 2) is Helium (He), which is in Period 1.
- Element B (Atomic number 10) is Neon (Ne), which is in Period 2.
- Element C (Atomic number 5) is Boron (B), which is also in Period 2.
Since both elements B and C are in Period 2, the correct answer is option B.
Question 9
4 / -1

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (Given ionization energy of H=2.18 ×10^–18J atom^–1and h = 6.625 × 10^–34 J s )

A
1.54 x 10¹⁵ s^-1

B
1.03 x 10¹⁵ s^-1

C
3.08 x 10¹⁵s^-1

D
2.00 x 10¹⁵ s^-1

Solution
Question 10
4 / -1

The orientation of an atomic orbital is governed by

A
Spin quantum number

B
Magnetic quantum number

C
Principal quantum number

D
Azimuthal quantum number

Solution

Magnetic quantum no. represents the orientation of atomic orbitals in an atom. For example p_x, p_y & p_zhave orientation along X-axis, Y-axis & Z-axis

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Chemistry Test 218

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Chemistry Test 218

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Question 1

1 × 109 cm s–1

1 × 106 cm s–1

1 × 105 cm s–1

1 × 1011 cm s–1

Solution

Question 2

Cobalt

Calcium

Potassium

Aluminium

Solution

Question 3

6.023 x 1023, 7.5 x 1023

6.023 x 1023, 15 x 1022

7.5 x 1022, 15 x 1022

15 x 1022, 7.5 x 1023

Solution

Question 4

Bond order is 2.5 since, five electrons are shared between N and O-atom

There is one unpaired electron hence, NO is paramagnetic

All are correct facts

Solution

Question 5

Second group

Eighteenth group

Third group

First group

Solution

Question 6

NO+

NO

O2

NO–

Solution

Question 7

noble gases

halides

alkaline

halogens

Solution

Question 8

A, B

B, C

C, A

A, B and C

Solution

Question 9

1.54 x 1015 s -1

1.03 x 1015 s -1

3.08 x 1015 s -1

2.00 x 1015 s -1

Solution

Question 10

Spin quantum number

Magnetic quantum number

Principal quantum number

Azimuthal quantum number

Solution

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1 × 10⁹ cm s^–1

1 × 10⁶ cm s^–1

1 × 10⁵ cm s^–1

1 × 10¹¹ cm s^–1

6.023 x 10²³, 7.5 x 10²³

6.023 x 10²³, 15 x 10²²

7.5 x 10²², 15 x 10²²

15 x 10²², 7.5 x 10²³

NO⁺

O₂

NO^–

1.54 x 10¹⁵ s^-1

1.03 x 10¹⁵ s^-1

3.08 x 10¹⁵s^-1

2.00 x 10¹⁵ s^-1