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Chemistry Test 219

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Chemistry Test 219
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  • Question 1
    4 / -1

    The oxidation number of Cl in Cl2O7 is

    Solution

    Cl show different oxidation state as -1 to +7 due to vacant d orbital.

    As oxygen is more electronegative than Cl.

    Oxygen size is small hence its more electronegative and show -2 oxidation states.

    2x + 7 (-2) = 0

    x = +7

     

  • Question 2
    4 / -1

    The standard reduction potentials E°, for the half reactions are as:

    Solution

     

  • Question 3
    4 / -1

    The binding of oxygen by haemoglobin (Hb) forming (HbO2), is partially regulated by the concentration of H3O + and dissolved CO2 in blood.

    Release of O2 is favoured when there is

    Solution

    During exercise muscle need energy hence consume more oxygen and produce more CO2 and lactic acid gets accumulated as well. According to bohr's effect oxygen binding affinity is inversely proportional to CO2 concentration and acidity. Thus favours the dissociation​ or release of O2.

     

  • Question 4
    4 / -1

    Fuel cells are _________ that are designed to convert the energy of combustion of fuels like hydrogen, methane, methanol, etc. directly into _________.

    Solution

    fuel cell is an electrochemical cell that converts the chemical energy of a fuel (often hydrogen) and an oxidizing agent (often oxygen) directly into electrical energy through a pair of redox reactions. 

    Fuel cells are different from most batteries in requiring a continuous source of fuel and oxygen (usually from air) to sustain the chemical reaction, whereas in a battery the chemical energy usually comes from metals and their ions or oxides that are commonly already present in the battery, except in flow batteries.

    Fuel cells can produce electricity continuously for as long as fuel and oxygen are supplied.

     

  • Question 5
    4 / -1

    Which of the following atom has been assigned only single oxidation number?

    Solution

    Fluorine is the most electronegative element. It can gain one electron.​

    Thus, Oxidation number = -1

    F+ e- → F-

    Due to very high (IE), it cannot lose electrons.

    (a) H- (-1), (H+ (+1)

    (b) O -2 in oxide, -1 in peroxide, and +2 in OF2

    (c) +3 in N2O3, -3 in NH3, +3 in HNO2, +5 in HNO3, + 1 in N2O

     

  • Question 6
    4 / -1

    Cl2 gas is passed into a solution containing KF, Kl and KBr, and CHCI3 is added. There is a colour in CHCI3 (lower) layer. It is due to

    Solution

     

  • Question 7
    4 / -1

    Which of the following reactions is a decomposition redox reaction?

    Solution

    Decomposition redox reaction leads to breakdown of a compound into two or more compounds at least one of which must be in the elemental state with change in oxidation number.

     

  • Question 8
    4 / -1

    In each of the following equilibria, pressure is made four times after equilibrium is set up. In which case yield of the product(s) is maximum?

    Solution

    The effect of pressure on equilibrium yield depends on the change in number of gas moles (Δng) between reactants and products.

    The general relationship is: yield ∝ (1 / pressure)Δng

    For (a) N2O4 ⇌ 2NO2: Δng = 2 - 1 = +1 Increasing pressure 4 times decreases product yield by (1/4)+1 = 1/4 times (yield decreases).

    For (b) C + H2O ⇌ CO + H2: Δng = (1 + 1) - 1 = 1 (Note: C is solid, so only gases count) Increasing pressure 4 times decreases product yield by (1/4)+1 = 1/4 times (yield decreases).

    For (c) N2 + 3H2 ⇌ 2NH3: Δng = 2 - (1 + 3) = 2 - 4 = -2 Increasing pressure 4 times increases product yield by (4)2 = 16 times (yield greatly increases).

    For (d) 2Fe + 3H2O ⇌ Fe2O3 + 3H2: Δng = 3 - 3 = 0 No change in number of gas moles, so pressure change has no effect on yield.

    Thus, the equilibrium where Δng is negative and largest in magnitude (case c) shows the maximum increase in product yield with increased pressure.

     

  • Question 9
    4 / -1

    The passage of current through a solution of certain electrolye results in the evolution of H2 at cathode and Cl2 at anode. The electrolytic solution is -

    Solution

    In this Cl  will oxidise to give Cl2 ,Na+ reduction potential has lower potential than water reduction polenlid so water will reduce to give H2.

     

  • Question 10
    4 / -1

    The decomposition of hydrogen peroxide to form water and oxygen is an example of

    Solution

    A disproportionation reaction is a particular type of redox reaction in which a single compound is transformed into two different compounds, one being reduced and the other being oxidized.

    The decomposition of hydrogen peroxide to form water and oxygen is a classic example of a disproportionation reaction.

     

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