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Chemistry Test 224

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Chemistry Test 224
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The following reaction takes place in the presence of

    Solution

    −NO2 group is reduced to –NH2 using H2/Pd.

     

  • Question 2
    4 / -1

    Ethers are :

    Solution

    Ethers are compounds which are basic in nature. There is no acidic H in the compound while it has a donor O atom.

     

  • Question 3
    4 / -1

    Acetylenic hydrogens are acidic because

    Solution

    The acidity of acetylene or 1--alkynes can be explained on the basis of molecular orbital concept according to which formation of C — H bond in acetylene involves sphybridised carbon atom. Now since s electrons are closer to the nucleus than p electrons, the electrons present in a bond having more s character will be correspondingly more closer to the nucleus.

    Thus owing to high s character of the C — H bond in alkynes (s = 50%), the electrons constituting this bond are more strongly held by the carbon nucleus (i.e., the acetylenic carbon atom or the sp orbital acts as more electronegative species than the sp2 and sp3 with the result the hydrogen  present on such a carbon atom (≡C — H) can be esily removed as a proton.

     

  • Question 4
    4 / -1

    Ethanol is converted into ethoxyethane,

    Solution

    In order to obtain ethoxy ethane from ethanol, the ethanol must be subjected to the effect of concentrated sulphuric acid at 413 Kelvin or 140°C as shown below:

     

  • Question 5
    4 / -1

    The molecular formula C5H12 contains how many isomeric alkanes?

    Solution

     The three isomeric alkanes of C5H12 are n-pentane, 2-methylbutane (isopentane), and 2,2-dimethylpropane (neopentane).

     

  • Question 6
    4 / -1

    In dehydrohalogenation reactions the preferred product is that alkene which has the greatest number of alkyl groups attached to the doubly bonded carbon atoms. This rule is known as:

    Solution

    In dehydrohalogenation reactions the preferred product is that alkene which has the greatest number of alkyl groups attached to the doubly bonded carbon atoms. This rule is also known as Saytzeff’s rule.

     

  • Question 7
    4 / -1

     The observed order of the stability of the cabocation is:

    Solution

    The observed order of the stability of the carbocation is:

    To solve this, recall the general order of carbocation stability:

    Tertiary (3°) > Secondary (2°) > Primary (1°) > Methyl

    This is due to:

    • Hyperconjugation

    • +I (inductive) effect of alkyl groups

    • Resonance (not involved here directly)

    Analyzing the given carbocations:

    • CH₃⁺ → methyl carbocation (least stable)

    • CH₃CH₂⁺ → primary (1°) carbocation

    • (CH₃)₂CH⁺ → secondary (2°) carbocation

    • (CH₃)₃C⁺ → tertiary (3°) carbocation (most stable)

    Correct stability order:

    CH₃⁺ < CH₃CH₂⁺ < (CH₃)₂CH⁺ < (CH₃)₃C⁺

     

  • Question 8
    4 / -1

    Phosgene is a common name for

    Solution

    Carbonyl chloride (COCl2).

     

  • Question 9
    4 / -1

    Which one of the following compounds has the most acidic nature?

    Solution

    The presence of electron withdrawing substituent increases the acidity while electron releasing substituent, when present, decrease the acidity.

    Phenyl is an electron withdrawing substituent while -CH3 is an electron releasing substituent, Moreover, phenoxide ion is more resonance stabilised as compared to benzoyl oxide ion, thus, release proton more easily. That's why is a strong acid among the given.

     

  • Question 10
    4 / -1

    Chlorobenzene is prepared commercially by

    Solution

     

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