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Chemistry Test 81

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Chemistry Test 81
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Weekly Quiz Competition
  • Question 1
    4 / -1

    Which of the following are d-block elements but not regarded as transition elements?

    Solution

    Transition elements are characterized by partially filled (n-1) d subshells.

    Zn, Cd and Hg are not regarded as transition elements as they have completely filled (n-1)d subshell.

    The electronic configuration of zinc is [Ar]3d104s2.

    The electronic configuration of cadmium is [Kr]4d105s2.

    The electronic configuration of mercury is [Xe]5d106s2.

    Hence, the correct option is (B).

     

  • Question 2
    4 / -1

    The conductivity of 0.05M solution of MgCl2 is 194.5Ω−1 cm2 mol−1 at 25∘C. A cell with electrodes that are 1.50 cm2 in surface area and 0.5 cm apart is filled with the above solution. The resistance shown by the solution is

    Solution

     

  • Question 3
    4 / -1

    Which of the following is not an aromatic compound?

    Solution

    1,3,5-Cycloheptatriene is a non-aromatic compound. 

    The high stability and the characteristic chemical behavior of benzene are called aromatic character or aromaticity, respectively. 

    Compounds that meet Hückel's rule but do not fulfill one of the other prerequisites for aromaticity are called non-aromatic. Not only are they less stable than aromatic compounds, but their chemical behavior is quite dissimilar, as well.

    Hence, the correct option is (D).

     

  • Question 4
    4 / -1

    A gas X has Cp and Cv ratio as 1.4, at NTP 11.2L of gas X will contain number of atoms

    Solution

     

  • Question 5
    4 / -1

    Fused NaCl on electrolysis gives ………….. on cathode.

    Solution

    On electrolysis of molten or fused sodium chloride, the following reaction occurs:

    NaCl(l))→Na+(l)+Cl−(l)

    In molten NaCl there are Na+ and Br− ions.

    At the cathode which is a negative terminal, cations will be reduced. At anode which is a positive terminal, anions will be oxidized.

    So, sodium is deposited at the cathode.

    Hence, the correct option is (D).

     

  • Question 6
    4 / -1

    What is the decreasing order of dipole moments of the following molecules?

    1. Toluene

    2. o-dichloro benzene

    3. p-dichloro benzene

    4. m-dichloro benzene

    Solution

    p-dichlorobenzene < Toluene < m-dichlorobenzene < o-dichlorobenzene.

    The dipole moment of p – dichlorobenzene is zero due to symmetrical structure. 

    o- and m-dichlorobenzene have higher dipole moments than toluene due to the high electronegativity of chlorine than the –CH3 group. o-dichlorobenzene has a higher dipole moment due to a lower bond angle than the m-isomer.
    Hence, the correct option is (C).

     

  • Question 7
    4 / -1

    ABCD is a cyclic process explaining the thermodynamic process. What is the work done by the system in the cycle?

    Solution

     

  • Question 8
    4 / -1

    A gas X with disagreeable odour reduces silver nitrate solution to give metallic silver and is itself oxidized to Y. Y is a dibasic acid with reducing properties. It is slowly oxidized in air to a tribasic acid Z. Though Z is a tribasic acid, it behaves in an aqueous solution mostly as a dibasic acid. When a mixture of X and N2O is subjected to an electric spark, Z is obtained. Z is

    Solution

    Phosphorus is not electronegative enough. In order for H3PO4 be a strong acid, a proton must be able to easily fall off. Along with the higher electronegativity of N relative to P, the extra oxygen makes HNO3 a strong acid, while the lack thereof makes H3PO4 weak.

    H3PO4 + 4N2 → PH3 + 4N2O

    Phosphoric Acid + Dinitrogen = Phosphine + Nitrous Oxide
    Hence, the correct option is (C).

     

  • Question 9
    4 / -1

    A 0.1M aqueous solution of a weak acid is 2% ionised. If the ionic product of water is 1×10−14 mol2dm−6, then [OH ] is

    Solution

     

  • Question 10
    4 / -1

    In which of the following compounds, nitrogen exhibits the highest oxidation state?

    Solution

    Oxidation states of Nitrogen in the following compounds:

    N3H - oxidation state of nitrogen =−1/3

    NH2OH - oxidation state of nitrogen =−1

    N2H4 - oxidation state of nitrogen =−2

    NH3 - oxidation state of nitrogen =−3

    Hence, the correct option is (A).

     

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