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NEET Test 10

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NEET Test 10
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The hybridisation of xenon in XeF6, XeF4 is

    Solution

    XeF6 has one lone pair and six bond pairs of electrons, thus the hybridisation of XeF6 is sp3d3
    XeF4 has one two lone pairs and four bond pairs, thus its hybridisation is sp3d2.

     

  • Question 2
    4 / -1

    The colloidal mixture of solid and gas is called as

    Solution

    An aerosol is a colloid of fine solid particles or liquid droplets, in air or another gas. Aerosols can be natural or anthropogenic. Examples of aerosols are fog, dust etc.

     

  • Question 3
    4 / -1

    Nucleus as a cell organelle was first described by ______ .

    Solution

    nucleus as a cell organelle was first described by Robert brown as early as 1831.

     

  • Question 4
    4 / -1

    Which one of the following is being utilized as a source ofbio- diesel in the Indian countryside?

    Solution

    Euphorbia lathyrus contains mixture of trepan which can be converted into gasoline .Melvin Calvin was the first to identify plants which can be used to form biodiesel like petroleum , oil etc. Such plants belong to family Asclepiadaceae, Euphorbiaceaea, Aocynacaeae.

     

  • Question 5
    4 / -1

    Golden rice is a genetically modified Crop plant where the incorporated gene is meant for biosynthesis of

    Solution

    Golden rice is a variety of genetically engineered rice in which two genes two genes are incorporated in order to the production and accumulation of β-carotene in the grains.

     

     

  • Question 6
    4 / -1

    Haemophilia is treated by which of the transgenic products?

    Solution

    Factor VIII is used for the treatment of haemophilia.

     

  • Question 7
    4 / -1

    In reference to DNA polymerase III, which statement is wrong?

    Solution

    DNA polymerase III is not used for PCR. Taq polymerase is used.

     

  • Question 8
    4 / -1

    A bacterial cell lacking restriction enzymes will show which of the following features

    Solution

    Restriction enzymes are a part of restriction modification system in bacteria. If it were not present, then bacteriophages would have easily attacked the cells and lysed them. Restriction enzymes cleave bacteriophage genetic material which is injected by phages into the bacteria.

     

  • Question 9
    4 / -1

    Middle lamella is mainly composed of

    Solution

    Middle lamella is mainly composed of calcium pectate and magnesium pectate. It is the cementing layer between the cells. Pectin is composed of galacturonic acid that has the ability to form salt with calcium and magnesium.

     

  • Question 10
    4 / -1

    The most thoroughly studied of the known bacteria-plant interactions is the :

    Solution

    Interaction of Agrobacterium tumefaciens with plants are mostly studied form of bacterial-plant interaction, it is also called natural plant genetic engineer.

     

  • Question 11
    4 / -1

    During gamete formation, the enzyme recombinase participates during

    Solution

    Crossing over is the exchange of genetic material between homologous chromosomes that requires enzyme recombinase. Crossing over occurs in the pachytene stage of prophase I.

     

  • Question 12
    4 / -1

    What would be the number of chromosomes of the aleurone cells of a plant with 42 chromosomes in its root tip cells?

    Solution

    If a root tip has 42 chromosomes, that means 2n=42. 

    Aleurone layer, outermost layer of the endosperm of seed, has 3n chromosomes. 

    Root tip= 2n=42 

    N=21 

    Aleurone layer 3n=3*21=63

     

  • Question 13
    4 / -1

    Two systems are in thermal equilibrium. The quantity which is common for them is

    Solution

    The quantity which is common for them is Temperature. 
    Hence, option C is correct.

     

  • Question 14
    4 / -1

    We consider a thermodynamic system. If ΔU represents the increase in its internal energy and W the work done by the system, which of the following statements is true?

    Solution

    An isothermal process is a constant temperature process. In this process, 

    T = constant or ΔT = 0. 

    ∴ΔU = nCv ΔT = 0 

    An adiabatic process is defined as one with no heat transfer into or out of a system. Therefore, Q = 0. From the first law of thermodynamics. 

    W = –ΔU or ΔU = –W 

    Hence, option A is correct.

     

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