NEET Test 131

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NEET Test 131

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Weekly Quiz Competition

Question 1
4 / -1

Calculate the enthalpy of the formation of H₂O. Is the reaction an exothermic or endothermic reaction?

A
- 333.14 kJ mol^-1

B
+333.14 kJ mol^-1

C
- 285.83 kJ mol^-1

D
+285.83 kJ mol^-1

Solution

The reaction is as follows:

2H₂ + O₂ ------------> 2H₂O

This means that for every 2 molecules of Hydrogen gas, one molecule of Oxygen is needed to make 2 molecules of water

To calculate the enthalpy of this reaction, we use the equation:

Enthalpy of reaction = (Enthalpy of products) - (Enthalpy of reactants)

The Enthalpy of Formations for each molecule are:

H₂ = 0 kJ/mol

O₂= 0 kJ/mol

H₂O = -285.83 kJ/mol

From the equation given earlier, we can put the numbers in and get

Enthalpy = -285.83 - (0+0)

This means Enthalpy of formation of water = -285.83 kJ/mol
Question 2
4 / -1

A bus starts to move with an acceleration of 1 m/s². A man, who is 48 m behind the bus, runs to catch it with a constant velocity of 10 m/s. In how much time will he catch the bus?

A
8 sec

B
10 sec

C
14 sec

D
16 sec

Solution
Question 3
4 / -1

A particle is projected vertically with speed V from the surface of the earth. Maximum height attained by the particle, in terms of the radius of earth R,V and g is (V escape velocity, g is the acceleration due to gravity on the surface of the earth).

A

B

C

D

Solution
Question 4
4 / -1

In which of the following, gametophyte is not independent free living?

A
Pteris

B
Pinus

C
Funaria

D
Marchantia

Solution

In gymnosperms (like Pinus), the male and female gametophyte do not have an independent free living existence. They remain within the sporangia retained on the sporophytes i.e., female gametophyte (within megasporangium) and male gametophyte (within microsporangium). In bryophytes like Marchantia and Funaria, the main plant body is a gametophyte which is independent and the sporophyte is partially or fully dependent on gametophytic generation. In pteridophytes (like Pteris), gametophyte is usually independent and sporophyte is the dominant phase in the life cycle.
Question 5
4 / -1

Two cars A and B travel along the same road in the same direction from the same starting place. Car A maintains a speed of 50 km/h and car B of 60 km/h, but B starts one hour later. How many hours will it take for B to overtake A?

A
2

B
3

C
4

D
5

Solution

Car A is ahead of car B by 50 Km before car B leaves the starting point. In the first hour after car B leaves, car A will have traveled 120 Km, 2 Hrs × 50 km/h= 100 Km.

Remember car A left one hour before car B. Car B in the first hour from departure will have traveled 60 Km at 75 Km/h.

The third hour after departure car A will have traveled 180 km. (3 Hrs × 60 Km/h =180 Km)

Car B will be in the second hour since departure traveling at 60 Km/h. (2 Hrs× 60 Km/h= 120 Km).

Car A in its 3rd hr.has now traveled 180 km and car B in its 2nd Hr has now traveled 150 Km. Car B has now closed the distance from 60 Km to 30 Km from Car A.

In the 4th hour after departure Car, A will have traveled 240 Km. (4Hrs.× 60 Km/h= 240 Km.

Car B after leaving the starting point 1 Hr after Car A will be in its 3rd Hr of travel. ( 3 Hrs × 60 Km/h = 180 Km.

Car A Has now completed 5 Hrs of travel and has gone 300 km. at 60 Km/h. ( 5 Hrs × 50 Km/h= 250 km).

Car B after 4 Hrs. of travel at 60 Km/h has now travelled the same distance as car A. ( 4 Hrs ×60 Km/h =240 Km).

Car B would need to complete 4 Hrs of traveling to catch up and overtake Car A who had a 50 Km head start over car B.
Question 6
4 / -1

A particle moves along x-axis in such a way that its coordinate (x) varies with time (t) according to the expression, x = 2 − 5t + 6t². Then the initial velocity of the particle is

A
- 5 m / sec

B
- 3 m / sec

C
6 m / sec

D
3 m / sec

Solution
Question 7
4 / -1

Chemically hormones are:

A
Biogenic amines only

B
Proteins, steroids and biogenic amines

C
Proteins only

D
Steroids only

Solution

Hormones are chemical messengers formed by endocrine cells. Chemically hormones are of the following types: Aminescomposed of amino group e.g., Melatonin.

Amino acids - e.g. Thyroxine

Peptides - e.g. Insulin

Insulin Steroids - e.g. Aldosterone
Question 8
4 / -1

A feather is dropped on the moon from a height of 1.40 meters. The acceleration due to gravity on the moon is 1.67 m/s². Determine the time for the feather to fall to the surface of the moon. (in s):

A
1.2

B
1.9

C
0.29

D
1.29

Solution
Question 9
4 / -1

A bar magnet is dropped between a current carrying coil. What would be its acceleration?

A
g downwards

B
Greater than g downwards

C
Less than g downwards

D
Bar will be stationary

Solution

So, due to change in the flux emf is induced in the coil and by Lenz's law current flow in the direction which opposes the change in a magnetic field. So, the force due to this current-induced magnetic field opposes the motion of the bar magnet. Therefore, the net acceleration of fall is less than g.
Question 10
4 / -1

To detect the reducing and non reducing sugars, which of the following test is used?

A
Molisch's test

B
Biuret test

C
Fehling's test

D
Million's test

Solution

(A) Molisch's test is a chemical test which is used to check for the presence of carbohydrates in a given analyte.

(B) The biuret test, also known as Piotrowski's test, is a chemical test used for detecting the presence of peptide bonds. In the presence of peptides, a copper (II) ion forms mauve-colored coordination complexes in an alkaline solution.

(C) Fehling’s test is used for reducing sugars and non-reducing sugars, supplementary to the Tollens’ reagent test. The test was developed by German chemist Hermann von Fehling in 1849.

(D) Millon's reagent is an analytical reagent used to detect the presence of soluble proteins.