NEET Test 182

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NEET Test 182

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Weekly Quiz Competition

Question 1
4 / -1

Two photons of the same frequency are produced due to the annihilation of a proton and antiproton. Wavelength of the proton so produced is:

A
1.1 × 10⁻¹⁴ m

B
1.3 × 10⁻¹⁵ m

C
1.7 × 10⁻¹⁷ m

D
1.9 × 10⁻¹⁹ m

Solution

Two photons of the same frequency are produced due to the annihilation of a proton and antiproton.

Question 2

4 / -1

Match columns I and II, and choose the correct combination from the options given:

Column I	Column II
(a) Selaginella	(i) Psilopsida
(b) Equisetum	(ii) Lycopsida
(c) Adiantum	(iii) Sphenopasida
(d) Dryopteris	(iv) Pteropasida

i-a, ii-b, iii-c, iv-d

iii-d, iv-c, i-b, ii-a

ii-a, iii-b, ii-d, iv-c

iv-c, ii-a, iii-b, iv-d

Solution

Pteridophytes are seedless vascular plants that reproduce by means of spores and they are first land plants also. Pteridophyta is further divided into four classes i.e. Psilopsida, Lycopsida, Sphenopsida, and Pteropsida.

Selaginella belongs to Lycopsida and there is a ligule present at the base of each sporophyll and microsporophyll.

Equisetum belongs to Sphenopsida and it is a living fossil. This plant is also known by another name i.e., horsetail.

Adiantum, Dryopteris and Pteris belong to Pteropsida and they have large dissected leaves

Psilotum belongs to Psilopsida and is characterized by the absence of roots and the presence of rhizoids.

Question 3
4 / -1

Carotenoids are:

A
Glycoproteins

B
Hydrocarbons

C
Polysaccharides

D
Lipoproteins

Solution

Carotenoids are the plant pigments that are responsible for imparting bright red, yellow and orange color in the plants. These are water-insoluble pigments, unsaturated molecules built up of isoprene units and are related to phytol structurally.
Question 4
4 / -1

Chemical A is used for water softening to remove temporary hardness, A reacts with Na₂CO₃ to generate caustic soda. When CO₂ is bubbled through A, it turns cloudy. What is the chemical formula of A?

A
CaCO₃

B
CaO

C
Ca(OH)₂

D
Ca(HCO₃)₂

Solution

The chemical A is calcium hydroxide (Ca(OH)₂). It is used for water softening to remove temporary hardness. It reacts with sodium carbonate to form caustic soda.

Na₂CO₃+ Ca(OH)₂→ CaCO₃↓ + NaOH

With carbon dioxide gas, it forms calcium carbonate which turns lime water milky.

Ca(OH)₂+ CO₂→ CaCO₃↓ + H₂O
Question 5
4 / -1

Temporary hardness of water can be removed by heating it with

A
SO₂

B
CaO

C
CO₂

D
NH₃

Solution

Temporary hardness of water can be removed by heating the water. Liming can soften the water with the use of calcium hydroxide, this chemical causes the calcium and magnesium carbonate to precipitate out as well.
Question 6
4 / -1

The solubility product of silver bromide is 5 × 10⁻¹³. The quantity of potassium bromide with molar mass 120 g/mol to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is

A
5 × 10⁻⁷ g

B
5 × 10⁻⁸ g

C
1.2 × 10⁻⁹ g

D
6.2 × 10⁻⁵ g

Solution
Question 7
4 / -1

Casparian strip occurs in:

A
Pericycle

B
Endodermis

C
Epidermis

D
Cortex

Solution

The innermost layer of cortex forms endodermis, which has compactly arranged barrel shaped cells. The primary thin walled endodermis shows suberin deposition in form of bands or strips that run around the radial and end walls of the cells and forms Casparian strips.
Question 8
4 / -1

Which of the following fluorides does not exist?

A
NF₅

B
PF₅

C
AsF₅

D
SbF₅

Solution

Nitrogen cannot form pentahallide because it cannot expand its octet due to the unavailability of d-orbitals. That's why pentafluoride of NF₅ is not possible. The rest of the elements can expand their octet.
Question 9
4 / -1

Smooth ER does not play an important role in the biosynthesis of which of the following?

(a). Glycolipids

(b). Phospholipids

(c). Polysaccharides

(d). Cholesterol

A
Only (a) and (b)

B
Only (a),(b) and (c)

C
Only (a) and (c)

D
Only (c)

Solution

When the cells are grown on a carbon source different than glucose, then polysaccharides are synthesized using a different pathway. Gluconeogenesis (abbreviated GNG) is a metabolic pathway that results in the generation of glucose from non-carbohydrate carbon substrates such as phosphoenolpyruvate (PEP).
Question 10
4 / -1

Identify the parts marked 1, 2, 3, 4 and 5 in the given diagram.

A
1-Endocarp, 2-Coleoptile, 3-coleorhiza, 4-Endosperm, 5-Scutellum

B
1-Pericarp, 2-Coleoptile, 3-Radicle, 4-Endosperm, 5-Scutellum

C
1-Pericarp, 2-Coleoptile, 3-Plumule, 4-Endosperm, 5-Scutellum

D
1-Pericarp, 2-Coleoptile, 3-Coleorhiza, 4-Endosperm, 5-Scutellum

Solution

1-Pericarp, 2-Coleoptile, 3-Coleorhiza, 4-Endosperm, 5-Scutellum

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NEET Test 182

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NEET Test 182

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Question 1

1.1 × 10−14 m

1.3 × 10−15 m

1.7 × 10−17 m

1.9 × 10−19 m

Solution

Question 2

i-a, ii-b, iii-c, iv-d

iii-d, iv-c, i-b, ii-a

ii-a, iii-b, ii-d, iv-c

iv-c, ii-a, iii-b, iv-d

Solution

Question 3

Glycoproteins

Hydrocarbons

Polysaccharides

Lipoproteins

Solution

Question 4

CaCO3

CaO

Ca(OH)2

Ca(HCO3)2

Solution

Question 5

SO2

CaO

CO2

NH3

Solution

Question 6

5 × 10−7 g

5 × 10−8 g

1.2 × 10−9 g

6.2 × 10−5 g

Solution

Question 7

Pericycle

Endodermis

Epidermis

Cortex

Solution

Question 8

NF5

PF5

AsF5

SbF5

Solution

Question 9

Only (a) and (b)

Only (a),(b) and (c)

Only (a) and (c)

Only (c)

Solution

Question 10

1-Endocarp, 2-Coleoptile, 3-coleorhiza, 4-Endosperm, 5-Scutellum

1-Pericarp, 2-Coleoptile, 3-Radicle, 4-Endosperm, 5-Scutellum

1-Pericarp, 2-Coleoptile, 3-Plumule, 4-Endosperm, 5-Scutellum

1-Pericarp, 2-Coleoptile, 3-Coleorhiza, 4-Endosperm, 5-Scutellum

Solution

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1.1 × 10⁻¹⁴ m

1.3 × 10⁻¹⁵ m

1.7 × 10⁻¹⁷ m

1.9 × 10⁻¹⁹ m

CaCO₃

Ca(OH)₂

Ca(HCO₃)₂

SO₂

CO₂

NH₃

5 × 10⁻⁷ g

5 × 10⁻⁸ g

1.2 × 10⁻⁹ g

6.2 × 10⁻⁵ g

NF₅

PF₅

AsF₅

SbF₅