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Physics Test 203

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Physics Test 203
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Weekly Quiz Competition
  • Question 1
    4 / -1

    Under what condition angular frequency ω of the damped oscillator would be equivalent to angular velocity Ω of the undamped oscillator.

    Solution

     

  • Question 2
    4 / -1

    A point source of light is placed in front of a plane mirror.

    Solution

    Plane mirror always forms a virtual image of the real object for all the rays emitted by the object. So, when a point source of light is placed in front of a  plane mirror, all the reflected rays meet at a point when produced backward.

    Option B is correct.

     

  • Question 3
    4 / -1

    A node is a point where there is always

    Solution

    A node is a point along the medium of no displacement. The point is not displaced because destructive interference occurs at this point.

     

  • Question 4
    4 / -1

    Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?​

    Solution

    Beta(central Maxima) = 2 * lambda * D(distance of the screen) / d(distance between slits)

    beta = 2 m, wavelength = 500nm = 5 ×10-7m & d = 0.1mm = 1×10-4m

    ► 2 = 2 × 5 × 10-7 * D/10-4

    ► 1 = 5 × 10-3 D 

    ► D = 1000/5

    ► D = 200m

     

  • Question 5
    4 / -1

    Sodium has body-centered packing. The distance between the two nearest atoms is 3.7 Å. The lattice parameter is:

    Solution

     

  • Question 6
    4 / -1

    The knee voltage of a-n junction diode is 0.8 V and the with of the depletion layer is 2 μm. What is the electric field in the depletion layer?

    Solution

    Knee voltage- it is that forward voltage beyond which current start increasing rapidly, but below knee voltage variation of forward current and applied voltage is linear.

    The electric field in a region is given by, E=V/l.

    where V is the potential and l is the length or distance of the region in which it has to be measured.

    now, E=V/l

    E=0.8/2×10-6 m

    E= 0.4 MV/m

     

  • Question 7
    4 / -1

    When a pure semiconductor is heated, its resistance:

    Solution

    As temperature increases electrons from the valence band go to the conduction band, so conductivity increases hence resistance decreases.

     

  • Question 8
    4 / -1

    What is the order of forbidden gap in the energy bands of silicon?

    Solution

    Silicon has a forbidden gap of 1.1 eV at 300 K temperature.

     

  • Question 9
    4 / -1

    Sound waves travel at 350 m/s through a warm air and at 3500 m/s through brass. The wavelength of a 700 Hz acoustic wave as it enters brass from warm air

    Solution

     

     

  • Question 10
    4 / -1

    In the case of real gases, the equation of state, PV = RT (where P, V and T are respectively the pressure, volume and absolute temperature), is strictly satisfied only if corrections are applied to the measured pressure P and the measured volume V. The corrections for P and V arise respectively due to

    Solution

    According to kinetic theory of gases there is no intermolecular force of attraction between the molecule of gases but its not true as gases liquifise, at high pressure molecular interaction starts due to which pressure on the walls decreases as molecule dragged back so pressure exerted by real gas is less than ideal gas, due to repulsive forces molecule behave as small spheres and hence volume decreases

     

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