Physics Test 98

Result

Physics Test 98

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Question 1
4 / -1

Velocity at mean position of a particle execulting SHM is v₀then find velocity at a distance equal to half of the amplitude :-

A
√3v₀/ 2

B
v₀

C
2v₀/√3

D
2v₀

Solution
Question 2
4 / -1

Find the maximum velocity of SHM represented by

A
100

B
300

C
3

D
3π / 6

Solution

V_max = Aω = 3 × 100 = 300
Question 3
4 / -1

The SHM of a particle is given by . Calculate the magnitude of acc. at t = 1.5 sec :-

A
100 √2

B
50 √2

C
200 √2

D
100 / √2

Solution
Question 4
4 / -1

The displacement x (in m) of a particle performing SHM is related to time 't' (in sec) as . Find the frequency of oscillation :-

A
4 Hz

B
2 Hz

C
1 Hz

D
6 Hz

Solution

ω = 2πn = 4π

{n = 2 Hz}
Question 5
4 / -1

A simple pendulum is executing SHM with a time period 'T'. If the length of the pendulum is increased by 21% then find percentage increase in time period of the pendulum :-

A
5%

B
10%

C
15%

D
20%

Solution
Question 6
4 / -1

Two springs of spring constant K₁ and K₂ are connected as shown. Find the effective spring constant :-

A
K₁ + K₂

B
K₁ / K₂

C

D
K₁× K₂

Solution

Combination is parallel combination

∴ K_eq = K₁ + K₂
Question 7
4 / -1

Directions For Questions

Two SHM are represented by

...view full instructions

Find the ratio of amplitude of two SHM :-

A
1 : 4

B
2 : 1

C
4 : 1

D
3 : 1

Solution
Question 8
4 / -1

The displacement of particle varies acceleration to relation x = 4(cosπt + sinπt). Find the amplitude of particle :-

A
4√2

B
3√2

C
2√2

D
√2

Solution
Question 9
4 / -1

If a body of mass 0.98 kg is made to oscillate on a spring of force constant 4.84 N/m, then find the angular frequency of the body :-

A
2.2 rad/sec

B
3.2 rad/sec

C
2 rad/sec

D
1 rad/sec

Solution
Question 10
4 / -1

The fundamental frequency of a string stretched with a weight of 4 kg is 256 Hz. The weight required to produce its octave is

A
4 kg wt

B
8 kg wt

C
12 kg wt

D
16 kg wt

Solution