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Electric Charges and Fields Test - 4

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Electric Charges and Fields Test - 4
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Weekly Quiz Competition
  • Question 1
    4 / -1

    The constant k in Coulomb's law depends on

    Solution

    The value of k = (1/4πε0) = 8.854 x 10-12 C2 N-1 m-2 where ε0 is permittivity of free space.

  • Question 2
    4 / -1

    Which of the following statement is not a similarity between electrostatic and gravitational forces?

    Solution

    Electrostatic forces are both attractive and repulsive depending upon the type of charge, but gravitational forces is always attractive.

  • Question 3
    4 / -1

    SI unit of permittivity of free space is

  • Question 4
    4 / -1

    The force between two small charged spheres having charges of 1 x 10-7 C and 2 x 10-7 C placed 20 cm apart in air is

    Solution

    Here, q1 = 1 x 10-7 C, q2 = 2 x 10-7 C, r = 20cm = 20 x 10-2 m

  • Question 5
    4 / -1

    The nucleus of helium atom contains two proton that are separated by distance 3.0 x 10-15 m. The magnitude of the electrostatic force that each proton exerts on the other is

    Solution

    Charge of proton is qP = 1.6 x 10-19 C

    Distance between the protons is, r = 3 x 10-15m
    The magnitude of electrostatic force between protons is 

  • Question 6
    4 / -1

    Two insulated charged metallic spheres P and Q have their centres separated by a distance of 60 cm. The radii of P and Q are negligible compared to the distance of separation. The mutual force of electrostatic repulsion if the charge on each is 3.2 x 10-7 C is

    Solution

    Here, q1 = q2 = 3.2 x 10-7 C, r = 60cm = 0.6 m
    Electrostatic force,

  • Question 7
    4 / -1

    Two point charges of +3 μC and +4 μC repel each other with a force of 10 N. If each is given an additional charge of -6 μC, the new force is

    Solution

    Here, q1 = +3 μC, q2 = +4 μC, F = 10N
    q1 = +3 - 6 = -3 μC, q2 = +4 - 6 = -2 μC

  • Question 8
    4 / -1

    The ratio of magnitude of electrostatic force and gravitational force for an electron and proton is

    Solution

    Here, for an electron and a proton 

  • Question 9
    4 / -1

    The electrostatic attracting force on a small sphere of charge 0.2μC due to another small sphere of charge -0.4μC in air is 0.4N. The distance between the two spheres is

    Solution

    Here, q1 = 0.2 μC = 0.2 x 10-6 C
    q2 = 0.4 μC = -0.4 x 10-6 C, F = -0.4 N
    As F = 

    = 1.8 x 10-3
    ∴ r = (1.8 x 10-3)1/2 = 0.0424 m = 42.4 x 10-3 m

  • Question 10
    4 / -1

    Under the action of a given coulombic force the acceleration of an electron is 2.5 x 1022 ms-2. Then the magnitude of the acceleration of a proton under the action of same force is nearly

    Solution

    The acceleration due to given coulombic force F is 
    a = (F/m) or a ∝ (1/m) ...(1)
    ∴  where mc and mp are masses of electron and proton respectively

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