Current Electricity Test

Result

Current Electricity Test - 5

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Weekly Quiz Competition

Question 1
4 / -1

In a wheatstone bridge if the battery and galvanometer are interchanged then the deflection in galvanometer will

A
change in previous direction

B
not change

C
change in opposite direction

D
none of these

Solution

The deflection in galvanometer will not be changed due to interchange of battery and the galvanometer.
Question 2
4 / -1

In a Wheatstone’s network, P = 2Ω, Q = 2Ω, R = 2Ω and S = 3Ω. The resistance with which S is to be shunted in order that the bridge may be balanced is

A
1Ω

B
2Ω

C
4Ω

D
6Ω

Solution

Let x be the resistance shunted with S for the bridge to be balanced.
For a balance Wheatstone's bridge

or S' = 2Ω
From Figure

x = 6Ω
Question 3
4 / -1

Four resistances of 3Ω, 3Ω, 3Ω and 4Ω respectively are used to form a Wheatstone bridge. The 4Ω resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be

A
10Ω

B
11Ω

C
12Ω

D
13Ω

Solution

The bridge will be balanced when the shunted resistance is of the value of 3Ω
Question 4
4 / -1

Four resistors are connected as shown in the figure.

A 6V battery of negligible resistance, is connected across terminals A and C. The potential difference across terminals B and D will be

A
Zero

B
1.5V

C
2V

D
3V

Solution

The given figure is a circuit of balanced Wheatstone bridge as shown in the figure.

Points B and D would be at the same potential,
i.e., V_B − V_D = 0 volt
Question 5
4 / -1

Resistances P, Q, S and R are arranged in a cyclic order to form a balanced Wheatstone's network. The ratio of power consumed in the branches (P + Q) and (R + S) is

A
1 : 1

B
R : P

C
P² : Q²

D
P² : R²

Solution

For balanced Wheatstone's bridge
P/Q = R/S.....(i)
Power dissipation in resistance R with voltage V is V²/R.
∴
From equation (i)

⇒
Using (i), we get

∴