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Electromagnetic Induction Test - 8

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Electromagnetic Induction Test - 8
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  • Question 1
    4 / -1

    The magnetic flux passing normally through a coil is ø = 20 cos πt + t2 + 50t + 25m Wb What will be the induced emf at t = 1s?​

    Solution

    θ=20cos5πt+t2+50t+25 mWb
    We know that,
    Emf=dθ/dt=-20x5πsin5πt+2t+50+0
    At,t=1
    Emf=-100πsing5π+2+50
           =0+2+50
           =52V

  • Question 2
    4 / -1

    A copper rod moves parallel to the horizontal direction. The induced emf developed across its ends due earth’s magnetic field will be maximum at the

    Solution

    At the poles of the copper rod, the earth’s magnetic field will be more. This is explained with the help of Lorentz force where he explains that the magnetic field is generated due to the movement of charges.
     
    Earth’s magnetic field is defined as the magnetic dipole which is similar to bar magnet and is tilted 11° from the earth’s axis of rotation.
     

  • Question 3
    4 / -1

    The magnetic flux through a surface varies with time as follows:

    = 12t2 + 7t + 3
    here, is in milliweber and t is in seconds.
    What will be the induced emf at t = 5s?​

    Solution

    Given :
                ϕ=12t2+7t+C
    where, C is a constant, t is in sec, ϕ in milli-weber
    The induced e.m.f. in the loop at t=5, on differentiating the equation with respect to 't'.
              dtdϕ​=dtd​(12t2+7t+C)
                    =24t+7
     at            t=5
                    dtdϕ​=24×(5)+7
                              =120+7
                              =127 mV
     

  • Question 4
    4 / -1

    In Faraday’s experiment if the magnet is moved towards the coil, it results in ____________ in magnetic field B at any point on the wire loop. The _________ shows deflection. Thus emf is induced by changing B.

  • Question 5
    4 / -1

    What is the value of induced e.m.f if a wire is moved between the gap of two poles of a magnetin in 1 s and magnetic flux between the poles is 6 x 10-3 Wb?​

  • Question 6
    4 / -1

    Two similar circular co-axial loops carry equal current in the same direction. If the loops be brought nearer, the currents in them will

    Solution

    When the two loops are brought together, the flux linking the two loops increases. By Lenz's law a current will be induced such that it opposes this change of flux . Therefore to oppose the increase in flux, the current in the two loops will decrease, so the flux decreases.

  • Question 7
    4 / -1

    When a wire loop is rotated in a magnetic field, the direction of induced emf changes once in each

    Solution

    Flux of the magnetic field through the loop
    ϕ=B.Acosωt
    Emf= −dϕ/dt​=B.Aωsinωt
    ωt=0 to π,  sinωt=+ve
    ωt=π to2 π,  sinωt=−ve
    Hence, the direction of induced e.m.f. changes once in 1/2​ revolution.
     

  • Question 8
    4 / -1

    The induced e.m.f in a coil is given by ε = 100sin 100π volts. Calculate the number of rotations the coil makes per second.​

    Solution

    ε=100sinπV
    ε=ε0sinωt
    ω=100π
    2πn=100π
    n=50rps

  • Question 9
    4 / -1

    The motional emf produced across a wire moving through a magnetic field does not depend on its:

    Solution

    Motional emf= Bℓv
    It depends on magnetic field intensity, length and velocity. The diameter doesn't affect any of the factors.

  • Question 10
    4 / -1

    If we keep two similar loops made up of copper and constantan in a magnetic field for same amount of time, in which loop the induced e.m.f will be greater.

    Solution

    As the copper has high electrical conductivity. Hence, higher e.m.f would be induced in the copper loop.

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