System of Particles and Rotational Motion Test

Result

System of Particles and Rotational Motion Test - 9

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Question 1
4 / -1

A spherical solid ball rolls on a table. What fraction of its total K.E. is rotational K.E. ?

A
5/7

B
7/10

C
1/5

D
2/7

Solution
Question 2
4 / -1

A body is rolling down an inclined plane without slipping. How does the acceleration of the rolling body depend on its radius?

A
It is inversely proportional to the square root of radius

B
It is directly proportional to the square root of radius

C
It does not depend upon radius

D
It is directly proportional to the radius

Solution

The acceleration of a rolling body is independent of its mass and radius.
Question 3
4 / -1

Acceleration (a) of a body of radius R rolling down an inclined plane of inclination is given by

A

B

C

D
Question 4
4 / -1

What is the moment of inertia of a solid sphere about its diameter?

A

B

C

D

Solution

We have to consider solid sphere contribution of infinite small solid cylinder.
Icylinder = ½ MR²
dI = ½ dmr²
dm = pdV
dV = πr²dx
By substituting dV into dm
dm = pπr²dx
Now dm into dI
dI = ½ r²pπr²dx = ½ pπr⁴dx
Now, r² = R²-x²
dI = ½ pπ(R²-x²)²dx
Integrate both sides
I = ½ pπ 16/15 R²
P = M/V
P = M/4/3πR³ (density of sphere)
After substituting
I = 2/5MR²
Question 5
4 / -1

What is the coefficient of friction when a cylinder rolls down without slipping on an inclined plane?

A
μ = 1/2tanθ

B
μ = tanθ

C
μ = tanθ/3

D
μ = 1/3tanθ

Solution
Question 6
4 / -1

If a solid cylinder rolls up along a inclined plane with an initial velocity v. It will rise up to a height h equal to

A

B

C

D
Question 7
4 / -1

What will be the speed of center of mass, if a solid sphere of radius 20 cm which rotates at 2 rps along a straight line?

A
2.55 m/s

B
2.50 m/s

C
2.51 m/s

D
2.22 m/s

Solution

V = rw
V = 20 × 10^-2 × 2π(2)
V = 2.51 m/s
Question 8
4 / -1

Two discs A and B are mounted on a vertical axle. Suppose the discs have moment of inertia as I and 2 I respectively about an axis. Disc A is given angular velocity ω, using the potential energy of a spring compressed by x₁. Similarly the potential energy of a spring compressed by x₂ gives an angular velocity of 2ω to Disc B. Considering that both the discs rotate in same direction .Find the ratio x₁/ x₂:

A

B

C

D
Question 9
4 / -1

A small cylinder rolling with a velocity v along a horizontal surface encounters a smooth inclined surface. The height ‘h’ up to which the cylinder will ascend is

A
3v²/4g

B
v²/2g

C
3v²/2g

D
v²/4g

Solution

A body can roll along a surface only if the surface is rough. The body will roll up to the foot of the inclined smooth surface. It will continue to spin with the angular speed it has acquired, and will slide up to a certain height, maintaining its spin motion throughout the smooth surface. Its translational kinetic energy alone is responsible for its upward motion along the smooth incline so that the height up to which it will rise is given by
Question 10
4 / -1

The kinetic energy of a rolling wheel is

A

B

C

D

Solution

The total KE is the sum of translational KE and rotational KE.