Fluids Test

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Fluids Test - 10

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Question 1
1 / -0

Water is flowing continuously from a tap having an internal diameter 8 x 10^-3 m. The water velocity as it leaves the tap is 0.4 ms^-1. The diameter of the water stream at a distance 2 x 10^-1 m below the tap is close to

A
5.0 x 10^-3 m

B
7.5 x 10^-3 m

C
9.6 x 10^-3 m

D
3.6 x 10^-3 m

Solution

Diameter = 8 x 10^-3 m
Question 2
1 / -0

Two metal spheres are falling through a liquid of density 2×10³kg/m³ with the same uniform speed. The material density of sphere 1 and sphere 2 are 8×10³kg/m³ and 11×10³kg/m³ respectively. The ratio of their radii is

A
11/8

B

C
3/2

D

Solution

The terminal velocity of the spherical body of radius R, density ρ falling through a liquid of density σ is given by
Question 3
1 / -0

A long cylindrical glass vessel has a small hole of radius r at its bottom. The depth to which the vessel can be lowered vertically in a deep water bath without any water entering inside is (surface tension = T and d = density of water)

A
4T/rdg

B
5T/rdg

C
3T/rdg

D
2T/rdg

Solution

excess pressure = h dg,
Question 4
1 / -0

A candle of diameter d is floating on a liquid in a cylindrical container of diameter D (D>>d) as shown in figure. If it is buming at the rate of 2 cm/hour then the top of the candle will

A
remain at the same height

B
fall at the rate of 1 cm/hour

C
fall at the rate of 2cm/hour

D
go up the rate of 1 cm/hour

Solution

As the candle is burning at the rate of 2cm/hour. The length of candle is reduced at the rate of 2cm/hour. According to law of floatation, the weight of liquid displaced is equal to the weight of body. Initially this condition is satisfied with half of the length of candle below the liquid. To satisfy this condition again, the candle must remain half inside llquid. Therefore, the (L-1) cm length of candle remains inside liquid. The level of liquid will come up at the rate of 1 cm/hour. The top of candie will fall at the rate of 1 cm/hour.
Question 5
1 / -0

A ball of relative density 0.8 falls into water from a height of 2 m. The depth to which the ball will sink is (neglect viscous forces)

A
8 m

B
2 m

C
6 m

D
16 m

Solution

Velocity of ball just before striking water surface v = √2gh
Question 6
1 / -0

In the given figure, the velocity v₃ will be

A
2 m/s

B
4 m/s

C
1 m/s

D
3 m/s

Solution

= 1 m/s
Question 7
1 / -0

There is hole of area a at the bottom of a cylindrical of area A. Water is filled upto a height h and water flows out in t second. If water is filled to a height 4h, it will flow out in time

A
t/4

B
2t

C
4t

D
t/2

Solution
Question 8
1 / -0

There is a hole in the bottom of tank having water. If total pressure at bottom is 3 atm (1 atm=10⁵N/m²) then the velocity of water flowing from hole is

A
√400 m/s

B
√600 m/s

C
√60 m/s

D
None of these

Solution

Pressure at the bottom of the tank

Pressure due to liquid column

P₁ = 3 × 10⁵ − 1 × 10⁵ = 2 × 10⁵

and velocity of water v = √2gh
Question 9
1 / -0

The reading of spring balance when a block is suspended from it in air, is 6 N. This reading is changed to 40 N when the block is immersed in water. The specific gravity of the block is

A
3

B
2

C
6

D
3/2

Solution

Specific gravity or relative density
Question 10
1 / -0

If work W is done in blowing a bubble of radius R from soap solution, then the work done in blowing a bubble of radius 2R from the same solution is

A
W/2

B
2W

C
4W

D
2 1/3 W

Solution

If radius becomes double then work done will become four times.