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Fluids Test - 4

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Fluids Test - 4
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  • Question 1
    1 / -0

    An object of w and density ρ is submerged in liquid of density σ, its apparent weight will be

    Solution

     

  • Question 2
    1 / -0

    A person swimming in a fresh water pool swims, obeying

    Solution

    A person swimming in fresh water pool swims obeying 3 rd law of motion. He pushes water backward, water in turn pushes him forward and he swims.

     

  • Question 3
    1 / -0

    A container has a small hole at its bottom. Area of cross-section of the hole is A1 and that of the container is A2. Liquid is poured in the containor at a constant rate Q m3/s
    The maximum level of liquid in the container will be

    Solution

    Level in the container will become maxium when rate of inflow =rate of outelow. or,

     

  • Question 4
    1 / -0

    A rectangular vessel when full of water takes 10 minutes to be emptied through an orifice in its bottom. How much time will it take to be emptied when half filled with water

    Solution

     

  • Question 5
    1 / -0

    Two rain drops of same radii 'r', falling with terminal velocity 'v' merge and form a bigger drop of radius R. The terminal velocity of the bigger drop is

    Solution

    Terminal velocity

     

  • Question 6
    1 / -0

    Water flows along a horizonatl pipe whose cross-section is not constant. The pressure is 1 cm of Hg where the velocity is 35 cms−1. At a point where the velocity is 65 cms−1, the pressure will be

    Solution

    In horizontal pipe

    ∴ From Eq. (i),

    After solving, 0.89 cm of Hg.

     

  • Question 7
    1 / -0

    If two soaps bubbles of equal radii r coalesce  then the radius of curvature of interface between two bubble will be

    Solution

     

  • Question 8
    1 / -0

    A cylinrical vessel is filled with a liquid up to a height H. A small hole is made in the vessel at a distance y below the liquid surface as shown in figure. The  liquid emerging from the hole strike the ground at distance x

    Solution

    At h = H/2, maximum range is obtained, which is equal to H.

    Further Rh = RH−h

     

  • Question 9
    1 / -0

    Water from a tap emerges vertically down with an initial speed of 10ms−1. The cross-sectional area of tap is 10−4m2. Assume that the pressure is constant throughout the stream of water, and that the flow is steady. The cross sectional area of the stream 0.15 m below the tap is

    Solution

    Decrease in potential energy= increase is kinetic energy

     

    or

    Now from continuity equation,

    Velocity has become two times. Hence area of cross section will remain half.

     

  • Question 10
    1 / -0

    A solid uniform ball of volume V floats on the interface of two immiscible liquids (Fig.) The specific gravity of the upper liquid is ρ1 and that of lower one is ρ2 whilst the specific gravity of ball is ρ (ρ1<ρ<ρ2) The fraction of the volume of the ball in the upper liquid is

    Solution

    Let v be volume of sphere in the upper liquid and that in lower liquid is (V-v)

     

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