Fluids Test

Result

Fluids Test - 6

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A U-tube of base length I filled with same volume of two liquids of densities ρ and 2ρ is moving with an acceleration a on the horizontal plane. If the height difference between the two surfaces fopen to atmosphere) becomes zero, then height h is given by

A
al/g

B
3al/2g

C
2al/3g

D
al/2g

Solution

Writing pressure equation from one end to other end of tube

Since h = 3al/2g
Question 2
1 / -0

A faulty barometer contains some air which occupies 9.5 cc. If indicates 740 mm when a correct barometer indicates 750 mm, the volume the air would occupy under standard pressure

A
0.0.95 cc

B
0.125 cc

C
1.25 cc

D
12.5 cc

Solution

PV= constant

air pressure is 750-740= 10 mm of Hg and its volume is 9.5 cc

At 760 mm pressure, let the volume be v'

∴ PV= P'V'= constant

10 × 9.5 = 760V'

or
Question 3
1 / -0

A hole is made at the bottom of the tank filled with water (density= 1000 kg/m³). If the total pressure at the botton of the tand is three atmoshphere (1 atmosphere = 10⁵ N/m²), then the velocity of efflux is

A
√400 m/s

B
√200 m/s

C
√6400 m/s

D
√500 m/s

Solution

Difference in pressure energy= difference in kinetic energy

or
Question 4
1 / -0

Kerosene oil rises up in the wick of a lantern because of

A
diffusion of the oil through the wick

B
surface tension

C
buoyant force of air

D
the gravitational pull of the wick

Solution

Kerosene oil rises up in the wick of a lantern because of capillarity which arises due to surface tension.
Question 5
1 / -0

Three liquids of densioties d, 2d and 3d are mixed in equal proportions of weights. The relatice density of the mixture is

A
11/7 d

B
18/11 d

C
13/9 d

D
23/18 d

Solution

Let M be mass of each of the three liquids of density d, 2d, 3d respectively them density of mixture
Question 6
1 / -0

A capillary tube is dipped in a liquid. Let pressure at point A, B and C be p_A' p_B' p_C respectively then

A
p_A= p_B= p_C

B
p_A= p_B< p_C

C
p_A= p_C< p_B

D
p_A= p_C> p_B

Solution
Question 7
1 / -0

For the arrangement shown in the figure, the force at the bottom of the vessel is

A
200 N

B
100 N

C
20 N

D
2 N

Solution

F = p×A = (ρgh_total) A

= (10³×10×10)(100×10⁻⁴)

= 100 N
Question 8
1 / -0

A tank is filled to a height H. The range of water coming out of a hole which is a depth H/4 from the surface of water level is

A
2H/√3

B
√3H/2

C
√3H

D
3H/4

Solution
Question 9
1 / -0

Two rain drops falling through air have radii in the ratio 1:2. They will have terminal velocity in the ratio

A
4:1

B
1:4

C
2:1

D
1:2

Solution

The formula for terminal velocity is given by

So, v ∝ r²

Hence,
Question 10
1 / -0

Block A in the figure shown here hangs by a cord from dynamometer (spring balance) D₁ and is submerged in a liquid C contained in beaker B. The mass of beakerr is 1 kg and the mass of liquid is 1.5kg. The readings of dynamometers D₁ and D₂ of block A is pulled up out of the liquid?

A
D₁ will read 5 kg & D₂ will also read 5 kg

B
D₁ will read 7.5 kg & D₂ will read 2.5 kg

C
D₁ will read 2.5 kg & D₂ will also read 7.5 kg

D
D₁ will read 10 kg & D₂ will also read 2.5 kg

Solution

When body A is immersed in liquid, it experiences upthrust U, which makes dynamometer D₁ read apparant weight

= true weight - upthrust

= W_A− U = 2.5 kg wt

Dynamometer D₂ reads Weight of B + Weight of C + Reaction equal to the upthrust of A

or W_B+W_c+U = 7.5 kg wt

As W_B= 1 kg wt, W_C= 1.5 kg wt

1+1.5+U = 7.5 kg wt

∴ U = 5 kg wt

From (1) ∴ W_A= U+2.5 = 5+2.5 = 7.5 kg wt

Therefore, D₁ reads its true weight 7.5 kg wt and dynamometer D₂ reads weight of beaker and liquid in it which is 2.5 kg wt.