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Simple Harmonic...

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  • Question 1
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    Equation of simple harmonic motion of a particle is y = (0.4 m) sin314t, where time t is in second. Frequency of vibration of the particle is

  • Question 2
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    A particle starts SHM from the mean position. Its amplitude is A and time period is T. At the time when its speed is half of its maximum speed, its displacement is

  • Question 3
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    The acceleration of a particle in SHM is

  • Question 4
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    A particle moves in the XY plane according to the equation  The motion of the particle is along:

  • Question 5
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    A particle is performing SHM with amplitude A and angular velocity ω. The ratio of the magnitude of maximum velocity to maximum acceleration is

  • Question 6
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    Values of the acceleration A of a particle moving in simple harmonic motion as a function of its displacement x are given below

    The period of the motion is :

  • Question 7
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    The acceleration-time graph of a particle undergoing SHM is shown in the figure.

  • Question 8
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    A particle is executing SHM about origin along X-axis, between points A(α, 0) and B(-α, 0). Its time period of oscillation is T. The magnitude of its acceleration T/12 second after the particle reaches point A will be

  • Question 9
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    A particle executes linear oscillation such that its epoch is zero. The ratio of the magnitude of its displacement in 1st second and 2nd second is (Time period = 12 seconds)

  • Question 10
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    A simple pendulum attached to the ceiling of a stationary lift has a time period of 1 s. The distance y covered by the lift moving downward varies with time as y = 3.75 t2, where y is in meters and t is in seconds. If g = 10 m/s2, then the time period of the pendulum will be

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