Simple Harmonic...

The shape of the graph plotted between the velocity and the position of a particle executing simple harmonic motion is:

Select the wrong statement about simple harmonic motion.

A particle is executing SHM with time period T starting from the mean position. The time taken by it to complete 5/8 oscillations is:

A particle is executing S.H.M. between x = ± A. The time taken to go from 0 to A/2 is T₁ and to go from A/2 to A is T_2, then:

For a particle executing simple harmonic motion, the amplitude is A and the time period is T. The maximum speed will be:

A particle is executing S.H.M with an amplitude A and has maximum velocity v_0, its speed at displacament 3A/4 will be :

Two particles executing SHM of the same frequency meet at x = +a/2 while moving in opposite directions. The phase difference between the particles is:

The displacements of two particles executing SHM on the same line are given as

The phase difference between them at t=1 sec is:

For a particle showing motion under the force F= -5 (x - 2)², the motion is:

For a particle showing motion under the force F= -5(x - 2), the motion is: