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Electrostatics Test - 10

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    If 4 x 1020 eV of energy is required to move a charge of 0.25 C between two points, then what will be the potential difference between them?

    Solution

    W = 4 x 1020 eV = 4 x 1020 x 1.6 x 10-19 J = 64 JW = V x qV = 64/0.25 = 256 V

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