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Electric Current Test - 13

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Electric Current Test - 13
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  • Question 1
    1 / -0

    According to Kirchhoff’s Loop Rule

    Solution

    Kirchhoff’s loop rule is based on the principle of conservation of energy. The work done in transporting a charge in a closed loop is zero. The algebraic sum ( since potential differences can be both positive and negative) of potential differences around any closed loop is always zero.

  • Question 2
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    The Wheatstone bridge is balanced for four resistors R1,R2,R3 and R4 with a cell of emf 1.46 V. The cell is now replaced by another cell of emf 1.08 V. To obtain the balance again

    Solution

    The balance point of the Wheatstone’s bridge is determined by the ratio of the resistances. The change in the emf of the external battery will have no effect on the balance point.

  • Question 3
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    Resistance of a conductor is

    Solution

    According to Ohm’s law, V = IR. Therefore R= V/I

  • Question 4
    1 / -0

    Two cells of emf 1.25V , 0.75V and each of internal resistance 1Ω are connected in parallel. The effective emf will be

    Solution

    We want the Voltage difference VAB.
    let A and B be open and not connected to any thing.
    There is a current that flows from cell of larger emf to the cell of small emf.
    Call that current as  I Amperes.

    1.25 V - 0.75 V - I * R2 - I * R1 = 0

    I = 0.5 / (R1+R2)
    VAB =  -0.75 - I * R2 =  - 0.75 - 0.5 * R2 / (R1+R2)

    = - (0.75 R1 + 1.25 R2) / (R1+R2)

    = - ().75 * 1 + 1.25 * 1) / (1 + 1)  volts

    =  - 1 volts

  • Question 5
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    Flow of charges in direction of electrons is called 

    Solution

    The flow of electrons is termed electronic current. Electrons flow from the negative terminal to the positive.

  • Question 6
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    In the measurement of resistance by a metre bridge, the current is necessarily reversed through the bridge wire to eliminate

    Solution

    The connecting metal strips include a small resistance in the circuit called the end resistance.On reversing the current, the end resistance tends to get cancelled out.

  • Question 7
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     If the length of the filament of a heater is reduced by 10% the power of the heater will

    Solution

    Power P= V2/R​
    If length reduced 10% then new resistance of filament will be R′.
    R′=R−10% of R
    R′=0.9R
    Now new power of heater is P2​
    P2​= V2​​/R′ = V2/0.9R​​=1.1P
    % increase power=11%

  • Question 8
    1 / -0

    Resistance of a conductor is

    Solution

    According to Ohm’s law, V=I R. Therefore R=V/I

  • Question 9
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    According to Ohm's law

    Solution

    Ohm’s law states I is proportional to V.This holds good at steady temperatures and for the flow of constant current.

  • Question 10
    1 / -0

    Potentiometer is

    Solution

    Potentiometer is a long wire of uniform cross section made of manganin.

  • Question 11
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    The unit of current is

    Solution

    1. Newton is SI Unit of Force
    2. Joule is SI Unit of Work Done
    3. Coulomb is SI Unit of Charge
    Hence, the unit of current is Ampere.

  • Question 12
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    A Wheatstone bridge ABCD is balanced with a galvanometer between the points B and D. At balance the resistance between the points B and D is :

    Solution

    No current passes through the Galvanometer in the bridge balance condition.Therefore, the resistance between B and D is infinite.

  • Question 13
    1 / -0

    The instrument for the accurate measurement of the e.m.f of a cell is

    Solution

    • Both potentiometer and voltmeter are devices to measure potential difference.
    • EMF is the terminal p.d between the electrodes of a cell in open circuit, i.e., when no current is drawn from it.
    • Potentiometer measures the potential difference using null deflection method, where no current is drawn from the cell; whereas voltmeter needs a small current to show deflection.
    • So, accurate measurement of p.d is done using a potentiometer.

  • Question 14
    1 / -0

    Electromotive force is

    Solution

    • An electric field exists in the electrolyte between the positive and negative terminals of the battery.
    • In the external circuit, the current flows from the positive electrode to the negative electrode.
    • To maintain continuity, in the electrolyte, the current (positive charges) flow from the negative electrode (lower potential) to the positive electrode (higher potential).
    • Work done by the source in taking unit positive charge from lower to higher potential is called electromotive force.

  • Question 15
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    Drift is the random motion of the charged particles within a conductor,

    Solution

    The electrons in a conductor have random velocities and when an electric field is applied, they suffer repeated collisions and in the process move with a small average velocity, opposite to the direction of the field. This is equivalent to positive charge flowing in the direction of the field.

  • Question 16
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    Unit of Resistivity is

    Solution

  • Question 17
    1 / -0

    Potentiometer measures the potential difference more accurately than a voltmeter, because

    Solution

    Potentiometer measures the potential difference using null deflection method, where no current is drawn from the cell; whereas voltmeter needs a small current to show deflection. So, accurate measurement of p.d is done using a potentiometer.

  • Question 18
    1 / -0

    Meter Bridge is based on the principle of

    Solution

    Meter bridge is the application of wheatstone’s bridge. A Wheatstone bridge is an electrical network which is used to calculate the value of unknown resistance.

  • Question 19
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    A piece of copper and another of germanium are cooled from room temperature to 80K. The resistance

    Solution

    • Copper is a conductor and we know that for conductors, resistance is directly proprtional to temperature. Therefore on decreasing temperature resistance also decreases.
    • Whereas, germanium is a semiconductor and for semiconductors, resistance is inversely proportional to temperature.
    • So on decreasing temperature resistance increases.

  • Question 20
    1 / -0

    Unit of power is

    Solution

    Power is rate of doing work.P=W/t.The unit of power is J/s which is also called watt.

  • Question 21
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    In a potentiometer experiment, for measuring internal resistance of a cell, the balance point has been obtained on the fourth wire. The balance point can be shifted to fifth wire by

    Solution

    If the current due to the auxillary battery is decreased, the potential gradient will be decreases, so the balancing length increases.Thus null point will move to fifth wire.

  • Question 22
    1 / -0

    Meter Bridge is used to

    Solution

    With a known resistance in one of the gaps, the meter bridge is used to determine the value of unknown resistance by the formula. 

  • Question 23
    1 / -0

    According to Kirchhoff’s Junction Rule

    Solution

    Kirchhoff’s junction rule is based on the principle of conservation of charge. For steady currents, there can be no accumulation of charge in a junction. The currents entering a junction bring charge to the junction and the currents leaving a junction carry away the charge brought to the junction.

  • Question 24
    1 / -0

    Ammeter is always used

    Solution

    Ammeter is a device used to measure current. Since it has to allow the complete current flowing in the circuit through it, it has to be connected in series. For this reason, ammeters have very low values of resistances so that they do not add to the value of resistance connected in the circuit.

  • Question 25
    1 / -0

    The sensitivity of the potentiometer can be increased by:

    Solution

    • A potentiometer is considered to be sensitive if the potential gradient dV/dl is low.
    • Such a potentiometer can measure very small changes in potential difference.
    • Increasing the length of the potentiometer wire decreases the potential gradient. Its sensitivity increases. Increasing potential gradient decreases the sensitivity.
    • Increasing the emf of the primary cell and by decreasing the length, potential gradient increases.

  • Question 26
    1 / -0

    Direction of the conventional current

    Solution

    Current flows in a conductor due to the flow of negatively charged electrons. However, the direction of conventional current is taken to be opposite to the direction of flow of electrons. It can therefore be considered as the direction in which positive charges move.

  • Question 27
    1 / -0

    Kirchhoff’s second law is a consequence of

    Solution

    Kirchhoff's second law, also known as the Kirchhoff's voltage law (KVL) states that the sum of all voltages around a closed loop in any circuit must be equal to zero. This again is a consequence of conservation of energy.

  • Question 28
    1 / -0

    A battery is connected with a potentiometer wire. The internal resistance of the battery is negligible. If the length of the potentiometer wire of the same material and radius is doubled then

    Solution

    Potential gradient Is given by V/l. If V and l are constant, the potential gradient also remains constant. The change in the radius will cause a change in the current. This does not change the potential gradient.

  • Question 29
    1 / -0

    In a meter bridge experiment a balance point is obtained at a distance of 60 cm from the left end when unknown resistance R is in a left gap and 8 ohms resistor is connected in the right gap. When the position of R and 8 ohm resistor is interchanged the balance point will be at distance of

    Solution

    60/40 = l/100-l, = R/8

    so R=12

    now changed position 8 is proportional to l and 12 to (100-l)

    8/12 = l/100-l

    l = 40ohm

  • Question 30
    1 / -0

    A Wheatstone bridge is balanced for four resistors R1, R2, R3 and R4 with a Lech lanche cell between A and C and a galvanometer between B and D. The positions of the cell and the galvanometer are interchanged. The balance will

    Solution

    The balance point will not change . For balancing of wheatstone bridge four arms of resistors are responsible. Interchange the position of galvanometer and cell does not affect balancing of wheatstone bridge.
     

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