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Alternating Current Test - 7

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Alternating Current Test - 7
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  • Question 1
    1 / -0

    In a capacitance dominated RLC circuit

    Solution

    In a series RLC circuit there becomes a frequency point were the inductive reactance of the inductor becomes equal in value to the capacitive reactance of the capacitor. In other words, XL = XC.
    Series Resonance circuits are one of the most important circuits used electrical and electronic circuits.
     

  • Question 2
    1 / -0

    In an RLC circuit, which of the following is always used as a vector reference?

    Solution

    In an RLC circuit, the voltage is always used as a reference and according to the phase of the voltage, the phase of the other parameters is decided.

  • Question 3
    1 / -0

    A 1.0 mH inductance, a10μF capacitance and a 5.0 ohm resistance are connected series to an a.c. source. It is found that inductor and the capacitor show equal reactance. The reactance should be nearest to:​

    Solution

    From the formula we get,
    XL=XC
    ωL=1/ωC
    ⇒ω2=1/LC
    ⇒ω=1/√Lc
    ⇒ω=1/√10-3x10-5
    ⇒ω=104
    We also know that,
    XL=ωL
    ⇒XL=104x10-3
    ⇒XL=10 Ω
    Therefore,XL=XC=10Ω

  • Question 4
    1 / -0

    In which of the following cases the power factor is not equal to 1​

  • Question 5
    1 / -0

    What is the inductance of a choke required for a lamp running at 60 volt d.c consuming 5 A current connected to 110 volt, 50 Hz ac mains?

  • Question 6
    1 / -0

    Ac and dc both can be measured by

    Solution

    Hotwire instruments are based on the heat Irms2​Rt and/or power Irms2​R producing property of current. Hence it can measure both ac and dc current as both produce heat when passed through a conductor.

  • Question 7
    1 / -0

    What is the value of power factor in RLC circuit

  • Question 8
    1 / -0

    In a series LCR what will be phase difference between voltage drop across inductor and capacitor

    Solution

    Let’s keep this simple and to the point. We know that:
    1.in a series circuit the same current flows through each component
    2.the voltage across an ideal inductor L is 90˚ ahead of an AC current through it
    3.the voltage across an ideal capacitor C is 90˚ behind an AC current through it
    So putting these facts together we can conclude that given an AC series current the voltages across any L and C must have a phase difference of 180˚

  • Question 9
    1 / -0

    A resistance of 5 ohm and an inductance of 50 mH are connected in series with an a. c. I = 100 sin (100 t). What is the phase difference between the instantaneous current and voltage?​

    Solution

    Cosφ=R/Z=R/√R2/ ω2L2=5/√(25+(50)2x (0.1)2)
    =5/√(25+25)=1/√2
    ⇒φ=π/4

  • Question 10
    1 / -0

    Admittance is reciprocal of

    Solution

    In electrical engineering, admittance is a measure of how easily a circuit or device will allow a current to flow. It is defined as the reciprocal of impedance, analogous to how conductance & resistance are defined. The SI unit of admittance is the siemens (symbol S); the older, synonymous unit is mho, and its symbol is ℧ (an upside-down uppercase omega Ω). Oliver Heaviside coined the term admittance in December 1887. 
    Admittance is defined as
    Y=1/Z
    where
    Y is the admittance, measured in siemens
    Z is the impedance, measured in ohms
     

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