Charges & Magnetism Test

Result

Charges & Magnetism Test - 17

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Question 1
1 / -0

Ampere's circuital law is given by

A

B

C

D

Solution

The line integral of the magnetic field of induction around any closed path in free space is equal to absolute permeability of free space μ₀ times the total current flowing through area bounded by the path.
Ampere's circuital law is given by:
Question 2
1 / -0

Two identical current carrying coaxial loops, carry current I in opposite sense. A simple amperian loop passes through both of them once. Calling the loop as C, then which statement is correct?

A

B
the value of is independent of sense of C.

C
there may be a point on C where are parallel.

D
none of these
Question 3
1 / -0

A long straight wire in the horizontal plane carries a current of 75 A in north to south direction, magnitude and direction of field B at a point 3 m east of the wire is

A
4 x 10^-6 T, vertical up

B
5 x 10^-6 T, vertical down

C
5 x 10^-6 T, vertical up

D
4 x 10^-6 T, vertical down

Solution

From Ampere circuital law

The direction of field at the given point will be vertical up determined by the screw rule or right hand rule.
Question 4
1 / -0

If a long straight wire carries a current of 40 A, then the magnitude ol the field B at a point 15 cm away from the wire is

A
5.34 x 10^-5 T

B
8.34 x 10^-5 T

C
9.6 x 10^-5 T

D
10.2 x 10^-5 T

Solution

I = 40A
r = 15 cm = 15 x 10^-2 m
∴ = 5.34 x 10^-5 T
Question 5
1 / -0

The correct plot of the magnitude of magnetic field vs distance r from centre of the wire is, if the radius of wire is R

A

B

C

D

Solution

The magnetic field from the centre of wire of radius R is given by
B = ((μ₀I)/(2R²))r (r < R) ⇒ B ∝ r
and B = μ₀I/2πr (r > R) ⇒ B ∝ 1/r
From this descriptions, we can say that the graph (b) is a correct representation.