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Kinematics Test - 8

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Kinematics Test - 8
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  • Question 1
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    A particle experiences constant acceleration for 20 s after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 seconds, then

    Solution

    s = ut + 1/2at2

    u = 0 m/sec (body starts from rest)

    s1 = 1/2at2

    s1 = 1/2a(102 )

    s1 = 50a ------------------(1)

    In the next 10 seconds, distance travelled is s2.

    For the first 20 seconds, distance travelled will be s1 + s2.

    s1 + s2 = 1/2a(20)2

    s1 + s2 = 200a

    Therefore, s2 = 150a -----------(2)

    Now, from equation 1 and 2, we have

    s1/s2 = 50a/150a

    s2 = 3s1

     

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