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Surface Tension Test - 6

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Surface Tension Test - 6
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  • Question 1
    1 / -0

    A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. (Surface tension of mercury is 0.465 J/m2

    Solution

    Increase in surface energy or work done in splitting a big drop 4πR2T(n1/3−1)

    ⇒ W = 4π × (2×10−3)2 × 0.465(81/3−1) = 23.4 μJ

     

  • Question 2
    1 / -0

    If two soap bubbles of equal radii r coalesce then the radius of curvature of interface between two bubbles will be

    Solution

     

  • Question 3
    1 / -0

    The angle of contact between glass and mercury is

    Solution

    Mercury causes capillary depression with an angle of contact of about 1350 in a clean glass in contact with air.

     

  • Question 4
    1 / -0

    A mercury drop does not spread on a glass plate because the angle of contact between glass and mercury is

    Solution

    The mercury does not spread on a glass plate because the angle of contact between glass and mercury is obtuse.

     

  • Question 5
    1 / -0

    The value of contact angle for kerosene with a solid surface.

    Solution

    The angle of contact will be equal to zero as it completely wets the solid surface.

     

  • Question 6
    1 / -0

    Nature of meniscus for liquid of 00 angle of contact

    Solution

    When angle of contact = 0° then, the meniscus for liquid will be semi-spherical.

     

  • Question 7
    1 / -0

    A liquid wets a solid completely. The meniscus of the liquid in a sufficiently long tube is 

    Solution

    The liquid wets the solid completely, so angle of contact, θ < 90°. Then the meniscus will be concave when θ < 90°.

     

  • Question 8
    1 / -0

    For which of the two pairs, the angle of contact is same

    Solution

    Both liquids water and alcohol have same nature (i.e. wet the solid). Hence angle of contact for both is acute

     

  • Question 9
    1 / -0

    If soap bubbles of different radii are in communication with each other

    Solution

    temperature remains constant

    so, PV=P'V'

    the bubble ith large radius will have more volume and hence less pressure.

    So, the Air flows from the smaller into the larger one and larger bubble grows at the expense of the smaller one

     

  • Question 10
    1 / -0

    The surface tension of the soap solution is 25×10−3 Nm−1 . The excess pressure inside a soap bubble of diameter 1 cm is

    Solution

     

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