Motion in a Straight Line Test 10

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Motion in a Straight Line Test 10

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following statements are incorrect?
(i) Average velocity is path length divided by time interval.
(ii) In general, speed is greater than the magnitude of the velocity.
(iii) A particle moving in a given direction with a non-zero velocity can have zero speed.
(iv) The magnitude of average velocity is the average speed.

A
(ii) and (iii)

B
(ii) and (iv)

C
(i), (iii) and (iv)

D
All four

Solution

A particle moving in a given direction with non-zero velocity cannot have zero speed. In general, average speed is not equal to magnitude of average velocity. However it can be so if the motion is along a straight line without change in direction.
Question 2
1 / -0

A car is moving along a straight line OP as shown in the figure. It moves from O to P in 18 s and returns from P to Q in 6 s. Which of the following statements is not correct regarding the motion of the car?

A
The average speed of the car in going from O to P and come back to Q is 20 m s^-1

B
The average velocity of the car in going from O to P and come back to Q is 10 m s^-1

C
The average speed of the car in going from O to P and come back to O is 20 m s^-1

D
The average velocity of the car in going from O to P and come back to O is 20 m s^-1

Solution

From O to P and back to Q
From O to P and come back to O
Question 3
1 / -0

The area under velocity-time graph for a particle in a given interval of time represents

A
velocity

B
acceleration

C
work done

D
displacement

Solution

The area under the velocity-time graph represents the displacement over a given time interval.
Question 4
1 / -0

A cyclist moving on a circular track of radius 40m completes half a revolution in 40s. Its average velocity is

A
zero

B
4 πms⁻¹

C
2 ms⁻¹

D
8 πms⁻¹

Solution
Question 5
1 / -0

The position of an object moving along x-axis is given by x = a + bt² , where a = 8.5 m and b = 2.5 m s⁻² and t is measured in seconds. The average velocity of the object between t = 2 s and t = 4 s is

A
5 m s^-1

B
10 m s^-1

C
15 m s^-1

D
20 m s^-1

Solution

6(2.5)m s^-1= 15m s^-1