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Work And Energy Test - 7

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Work And Energy Test - 7
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  • Question 1
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    300 J of work is done in sliding a 2 kg block, up an inclined plane to a height of 10 meters. Taking value of acceleration due to gravity 'g' to be 10 m/s2, work done against friction is

    Solution

    Work done = 2 × 10 × 10 + wf
    (w= work done against friction)
    300 = 200 + wf
    w= 100J

     

  • Question 2
    1 / -0

    The following question has four choices out of which ONLY ONE is correct.

    A force of 60 N is applied on a body at an angle of 60° with a horizontal, and displaces it through 5 m along horizontal. What is the work done?

    Solution

    F = 60 N
    θ = 60o
    S = 5 m
    W = FS cos θ
    = 60 x 5 x cos 60o
    = 60 x 5 x 1/2 = 150
    = 150 J

     

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