Self Studies
Selfstudy
Selfstudy

Chemistry Test - 3

Result Self Studies

Chemistry Test - 3
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    3 / -1

    The given osazone can be formed by

    Solution

    Formation of osazone involves only C1 and C2 carbon atoms. The rest of the carbon atoms remains uneffected.

    Glucose and fructose differ only in the configurations of first and second carbon atoms remaining positions are similar. So they form same osazone.

    Hence option D is the correct answer.

  • Question 2
    3 / -1

    Consider the following compounds.

    Which of the above compounds has/have an active methylene group?

    Solution

    Active methylene group should have EWG around both sides.

    Hence option D is the correct answer.

  • Question 3
    3 / -1

    Identify position most favorable for aromatic substitution (EAS)

    Solution

    is activating group so it would activate ortho and para position for E.A.S but only para position is

    empty so EAS will take place there.

    Hence, option (b) is correct

  • Question 4
    3 / -1

    Polymer of prop – 2 – ene nitrile is-

    Solution

    Prop-2 - ene nitrile Polymer

    Hence (b) is correct answer

  • Question 5
    3 / -1

    Which of the following type of compound is used to increase the hardness of the silicone polymer.

    Solution

    Hydrolysis followed by condensation polymerization of RSiCl3 produces 3-D cross-linked silicones which are hard.

    Hence option B is the correct answer.

  • Question 6
    3 / -1

    Which will give only one product (excluding stereoisomer) when undergoing E2 reaction ?

    Solution

    Which are identical product

    Hence option (d) is correct

  • Question 7
    3 / -1

    Assume that a particular amino acid has isoelectric point as 6.0. In a solution at PH 1.0 which of the following will predominate.

    Solution

    In acidic medium Z witter ion

  • Question 8
    3 / -1

    [X3B ← NH3], in which of the following boric halide, tendency to accept electrons from nitrogen of ammonia will be least (X = halogens)

    Solution

    In BF3, due to F back bonding to B, least Lewis acid character is observed. So out of above four, BF3 will have least tendency to accept electron from NH3.

    Hence, option (D) is correct.

  • Question 9
    3 / -1

    End product in the reaction is,

    Solution

    Step 1.

    Acid base reaction

    Step 2.

    Hence (a) option is correct.

     

  • Question 10
    3 / -1

    The storage battery generally used in electric power station is:

    Solution

    Deep-cycle lead-acid (DCLA) battery provides a steady electric current over a long time period and these are all connected together to from a battery bank. The technology of lead-acid battery is uncomplicated and the manufacturing costs are low compared to other types of batteries. So, it is cost effective and it has good discharging characteristics.

    Hence option C is the correct answer/

  • Question 11
    3 / -1

    Consider the following conversions:

    Among P, Q, R and S, the aromatic compound is/are

     

    Solution

    All P, Q, R are aromatic in nature as explained below:

    (1) This is Friedel-Crafts alkylation reaction in which cyclopropyl methyl carbocation is formed.

    (2) Cyclopendiene reacts with strong base from cyclopentadienyl anion which is aromatic in nature.

    Hence option D is the correct answer.

  • Question 12
    3 / -1

    Major products is,

    Solution

    H-bond is available here hence stable.

    Hence answer is (C)

  • Question 13
    3 / -1

    In which of the following outer d-orbital complex magnetic moment

    (spin only) is √3 B.M.

    Solution

  • Question 14
    3 / -1

    Among given options maximum enol content is in-

    Solution

    In this H-bonding leads to enol stability hence most stable.

    Hence (b) option is correct

  • Question 15
    3 / -1

    In the above reaction Product A is-

    Solution

    The lone pair of Nitrogen will attack first because lone pair of oxygen is more stable

    Hence option (C) is correct

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now